CODEWITHSUNDEEP
pythonpython-3.x
Loop Z
Loop Z

Reputation: 13

How to remove the square brackets in output of the list?

items=['a', 'b', 'c', 'd', 'e']
print("The first 3 items in the list are: ")
for item in items[:3]:
    print(item)

#or
print("The first 3 items in the list are: " + str(items[:3]))

Q: How should I make the output of the 'first 3 items' to be horizontal(like the second code) but without the square brackets(like the 1st code)?

Upvotes: 1

Views: 329

Answers (4)

Flux
Flux

Reputation: 10920

You can use str.join(iterable), where str is the separator between the items in the iterable. For example:

items = ['a', 'b', 'c', 'd', 'e']
print('The first 3 items in the list are: ' + ', '.join(items[:3]))

This prints:

The first 3 items in the list are: a, b, c

In this case, ', ' is the separator between the items of the list. You can change it according to your needs. For example, using ' '.join(items[:3]) instead would result in:

The first 3 items in the list are: a b c

Upvotes: 2

schneebuzz
schneebuzz

Reputation: 380

There are several ways. The appropriate here (IMO) is to use

print("items are: " + ', '.join(items[:3]))

Which (depending on your python version) can be simplified to:

print(f'items are: {", ".join(items[:3])}')

or without the comma

Another way is to tell the print to not print linebreaks:

for item in items[:3]:
    print(item, end='')

Upvotes: 0

Todd
Todd

Reputation: 5385

This would do it:

print("The first 3 items in the list are: " + str(items[:3])[1:-1])

assuming you don't mind the items separated by commas.

Upvotes: 0

fizgi
fizgi

Reputation: 48

You can write print(item, end=" ") in your loop.

Upvotes: 0

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