CODEWITHSUNDEEP
iosarraysswift
user2875404
user2875404

Reputation: 3218

Swift check for nil in optional array

I have an Optional array and need to check a member for nil. Unfortunately that doesn't work like I have expected it to do. It seems like I have to unwrap it however at runtime I don't know whether the value in question is a String, an Int, another array etc. so casting doesn't help (I think)

var nilString: String? = nil

let arr = [1, nilString] as [Any]?

print(nilString)
print(arr?[1])

if (arr?[1] == nil) {
    print("is nil") // doesn't work
}

if case Optional<Any>.none = arr?[1] {
    print("nil")     //would expect this one 
} else {             //but
    print("not nil") //<-- gets printed
}

Alternative ideas on the structure are also welcomed.

Upvotes: 0

Views: 346

Answers (1)

Leo Dabus
Leo Dabus

Reputation: 236548

Your problem there is that you have declared your Array type as optional instead of declaring its elements. You just need to change your array declaration to[Any?]. Note that the use of Any it is not useful in most situations. I've been coding in Swift for more than 5 years and I've never needed to declare an element type as Any.

Upvotes: 1

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