CODEWITHSUNDEEP
javascriptjquery
cmplieger
cmplieger

Reputation: 7351

declaring a variable blocks my code

is something wrong here? declaring those variables stops the execution of my code :(

var color = $('fieldset input[type=checkbox]').data("color");
        if(color === orange){var bgy = '-1'}
        else{var bgy = '-37'};

If you need more info please ask me :)

Upvotes: -1

Views: 91

Answers (5)

Spencer Ruport
Spencer Ruport

Reputation: 35117

Define bgy outside the if block and just set the value inside.

Upvotes: 0

Mahesh KP
Mahesh KP

Reputation: 6446

Did you mean color=='orange'?

If it didn't help please alert the value of color.

Upvotes: 2

dexter
dexter

Reputation: 13583

Dude... whats orange in 

if(color === orange){var bgy = '-1'}

Use firebug :D

Upvotes: 0

Gaurav
Gaurav

Reputation: 28755

Probably you need to use

if(color === 'orange')

other wise

orange will be treated as variable which is undefined.

Upvotes: 0

mattsven
mattsven

Reputation: 23283

Nope, that should work fine...only thing I'd suggest is this:

var bgy;
var color = $('fieldset input[type=checkbox]').data("color");
if(color === 'orange'){ bgy = '-1' } else { bgy = '-37' };

Make sure jQuery's actually finding your element, and alert out the value of color to troubleshoot. Other than that, I'll need more code to go on...

Upvotes: 0

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