CODEWITHSUNDEEP
python-3.xdictionary
user11449974
user11449974

Reputation:

I want to print the dictionary in python

l = {}
name = [(str, input().split()) for i in range(0, 15)]
dob = [(int, input().split()) for i in range(0, 15)]
print({name[i]:dob[i] for i in range(len(dob))})

I want to print 15 items in a dictionary format of name as key and dateofbirth(dob) as value.What wrong I am doing? .....................................................................................

the error is:
Traceback (most recent call last):                                                                                                
  File "main.py", line 4, in <module>                                                                                             
    print({name[i]:dob[i] for i in range(len(dob))})                                                                              
  File "main.py", line 4, in <dictcomp>                                                                                           
    print({name[i]:dob[i] for i in range(len(dob))})                                                                              
TypeError: unhashable type: 'list'

Upvotes: 1

Views: 49

Answers (2)

ABO
ABO

Reputation: 178

The issue is not in the print() function but in the way you make up the first list: instead of pulling out the names, it gives you a (<class 'str'>, 'string') tuple that cannot be used as a key for a dictionary. The same happens with the 'dob' variable, but the issue is only with keys.

Try doing:

name = [input() for i in range(0, 15)] #this takes and returns the input. no need to convert to string
dob = [int(input()) for i in range(0, 15)] #this takes an input and returns it's numeric value

Upvotes: 1

kakkeuno
kakkeuno

Reputation: 140

I would do it like this (this returns a generator):

name = map(str, input().split())
dob = map(int, input().split())
print({n: d for n, d in zip(name, dob)})

If you want it to return a list instead:

name = list(map(str, input().split()))
dob = list(map(int, input().split()))
print({n: d for n, d in zip(name, dob)})

Upvotes: 0

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