CODEWITHSUNDEEP
javascriptarrayscompare
faezanehhabib
faezanehhabib

Reputation: 25

How compare third one in each array in each line?

If I have two array 

A = [ "B,C,D"
      "W,F,G"
      "M,S,E"
    ]
D = [E]

and want to compare D OR G with E (I mean the third one in each line)and If they are equal can show all the line for me. The third one in each line a part of each line and I want just compare the third one If it is equal show that line have equal variable . I wrote this code but didn't give me the response that I need have :

 for(var k=0 ; k<A.length ; k++){
    if(A[k].split(",")[2] === E) {
       finalSuccessServices = A;
       console.log(finalSuccessServices );
     }

How can I improve my code to get that line that have my equal variable?

Upvotes: 1

Views: 49

Answers (4)

Siva Kondapi Venkata
Siva Kondapi Venkata

Reputation: 11001

  1. Use split and destructure to get third element
  2. Compare third value and first (from array D)
  3. Console log and push to finalSuccessServices array.

const A = ["B,C,D", "W,F,G", "M,S,E"];
const D = ["E"];

const [first] = D;
const finalSuccessServices = [];
A.forEach(line => {
  const [,, third] = line.split(",");
  if (third === first) {
    console.log(line);
    finalSuccessServices.push(line);
  }
});

console.log("finalSuccessServices", finalSuccessServices);

Upvotes: 0

Ele
Ele

Reputation: 33726

You can use the function filter along with the function includes in order to select those lines which have a third letter within the array D. 

let A = [ "B,C,D", "W,F,G", "M,S,E" ],
    D = ["E"],
    result = A.filter(s => {
      let [,,C] = s.split(",");
      return D.includes(C);
    });
    
console.log(result);

Upvotes: 0

Addis
Addis

Reputation: 2530

You can use find() to get the matching string, provided you have a single match:

const A = [ "B,C,D",
      "W,F,G",
      "M,S,E"
    ];
const D = ['E'];

let result = A.find(str => str.split(',')[2] === D[0]);

console.log(result)

Upvotes: 1

Nina Scholz
Nina Scholz

Reputation: 386730

You could filter the array and have a look up with includes.

var array = ["B,C,D", "W,F,G", "M,S,E"],
    pattern = ['E'],
    result = array.filter(s => pattern.includes(s.split(',')[2]));

console.log(result);

If you need only the first one, take find.

var array = ["B,C,D", "W,F,G", "M,S,E"],
    pattern = ['E'],
    result = array.find(s => pattern.includes(s.split(',')[2]));

console.log(result);

Upvotes: 0

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