CODEWITHSUNDEEP
javascriptmathrandom
asifg
asifg

Reputation: 421

JavaScript - Math.random() - parameter

What changes adding the parameter in Math.random()?

For example:

Math.random() == Math.random(1234)

Upvotes: 8

Views: 19398

Answers (6)

RobG
RobG

Reputation: 147533

Read the specification:

15.8.2.14 random ( )

Returns a number value with positive sign, greater than or equal to 0 but less than 1, chosen randomly or pseudo randomly with approximately uniform distribution over that range, using an implementation-dependent algorithm or strategy. This function takes no arguments.

Upvotes: 9

mplungjan
mplungjan

Reputation: 178422

No official parameters. Have a look here: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Math/random

The confusion is understandable. Several sites have a seed in the function since it came from C / Java. More information about this ignored parameter here: Math.random() - Not random

If you want a better random number get one from here http://www.random.org/clients/http/ - you will need to wrap it in some server based client - see here for more information Cross domain ajax request from javascript file without help of server side code

UPDATE: Emailed the creator of random.org - he replied he is working on a jsonp implementation...

Upvotes: 4

CristiC
CristiC

Reputation: 22708

Math.random doesn't take params.

If you want to generate a random number between 2 intervals (a and b) you can use the formula:

math.random()*(b-a)+a

Upvotes: 13

Amareswar
Amareswar

Reputation: 2064

It will just ignore the passed parameter.

Upvotes: 3

John Green
John Green

Reputation: 13445

Nothing. There is no seed for Math.random in Javascript. Anything inside the function call will just be dropped.

Upvotes: 5

chrisfrancis27
chrisfrancis27

Reputation: 4536

It doesn't - Math.random() doesn't take any parameters... :)

Upvotes: 2

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