CODEWITHSUNDEEP
javamethodstry-catchthrow
Omar Ashraf
Omar Ashraf

Reputation: 45

I have a problem in java method code which returns the division of two numbers

In this code a division method is implemented, so i want to handle 3 cases where division is undefined using try catch and throws, but it gives me an error message that the division method must return float . package calculator3;

//Class implements interface public class implementation implements calc {

//Add function
    public int add(int x, int y) {
        int ans1 = x + y ; 
        return ans1 ;

    }

    //Divide function
    public float divide(int x, int y) throws RuntimeException{
        try {
            if(y == Double.POSITIVE_INFINITY || y == Double.NEGATIVE_INFINITY || y == 0 ) {
                throw new ArithmeticException("invalid_division");

            }
            else {        
                return x / y ;
            }

        }catch  (ArithmeticException invalid_division ) {
            System.out.println("invalid_division");
        }
}
}

Upvotes: 0

Views: 473

Answers (2)

ELinda
ELinda

Reputation: 2821

Your divide return type is float.

An int will never equal Double.POSITIVE_INFINITY or Double.NEGATIVE_INFINITY because those are not in their range of possible values.

The function will not throw an error if it is caught.

Taking above 3 points:

//divide
public float divide(int x, int y) throws ArithmeticException{
        if (y == 0) throw new ArithmeticException("invalid_division");
        return (float)x / y; // cast x to float so a float will result
}

Upvotes: 1

Nate Schreiner
Nate Schreiner

Reputation: 849

Your not actually throwing the exception once catching it so the compiler will complain that your missing a return in your divide() method.

add:

throw e;

to your catch clause

Upvotes: 0

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