CODEWITHSUNDEEP
javaxmljaxb
Udi
Udi

Reputation: 1110

JAXB annotation for class hierarchy

Hey, I have 2 classes. When I'm trying to create an XML structure from them, I only get the root element (A). Why? Am I using wrong annotations?

@XmlRootElement(name = "a")
@XmlAccessorType(XmlAccessType.FIELD)
public abstract class A{
    @XmlElement
    int a;

    protected A(){
    }
 }

@XmlAccessorType(XmlAccessType.FIELD)
public class B extends A{
    @XmlElement
    int b;

    protected B(){
    }
}

Upvotes: 5

Views: 6041

Answers (1)

Grzegorz Oledzki
Grzegorz Oledzki

Reputation: 24251

You probably need to use @XmlSeeAlso annotation in your top class:

@XmlSeeAlso(B.class)
@XmlRootElement(name = "a")
@XmlAccessorType(XmlAccessType.FIELD)
public abstract class A{

I wrote 'probably', because it depends on how do you set up your JAXB context. Basically you need to make sure all the classes which are supposed to be serialized are known to JAXB. If your B class is not mentioned anywhere else (e.g. as a property type of one of classes which are already known to JAXB), then JAXB has no chance to know how to serialize instances of B. The intention of @XmlSeeAlso annotation is to make sure JAXB looks into these listed classes too.

UPDATE:

Alternatively you can provide the list of all the subclasses when creating the JAXBContext object using JAXBContext.newInstance(Class...), e.g.:

   JAXBContext.newInstance(A.class, B.class);

instead of 

   JAXBContext.newInstance(A.class);

which you probably already do.

But my opinion this is a worse solution, because it makes you think of related classes every time you use JAXB in your code. In the top solution you set the relations once forever.

Upvotes: 7

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