Reputation: 23
I am just starting off with numpy and am trying to create a function that takes in an array (x), converts this into a np.array, and returns a numpy array with 0,0,0,0 added after each element.
It should look like so:
input array: [4,5,6]
output: [4,0,0,0,0,5,0,0,0,0,6,0,0,0,0]
I have tried the following:
import numpy as np
x = np.asarray([4,5,6])
y = np.array([])
for index, value in enumerate(x):
y = np.insert(x, index+1, [0,0,0,0])
print(y)
which returns:
[4 0 0 0 0 5 6]
[4 5 0 0 0 0 6]
[4 5 6 0 0 0 0]
So basically I need to combine the output into one single numpy array rather than three lists.
Would anybody know how to solve this?
Many thanks!
Upvotes: 1
Views: 1838
Reputation: 1259
Use the numpy .zeros function !
import numpy as np
inputArray = [4,5,6]
newArray = np.zeros(5*len(inputArray),dtype=int)
newArray[::5] = inputArray
In fact, you 'force' all the values with indexes 0,5 and 10 to become 4,5 and 6.
so _____[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
becomes [4 0 0 0 0 5 0 0 0 0 6 0 0 0 0]
>>> newArray
array([4, 0, 0, 0, 0, 5, 0, 0, 0, 0, 6, 0, 0, 0 ,0])
Upvotes: 3
Reputation: 468
I haven't used numpy to solve this problem,but this code seems to return your required output:
a = [4,5,6]
b = [0,0,0,0]
c = []
for x in a:
c = c + [x] + b
print(c)
I hope this helps!
Upvotes: 3