Reputation: 11
I made this code on Flask:
from flask import Flask
app = Flask(__name__)
@app.route('/')
def index():
return "hi"
Even so, fi I try to run it with flask run
it shows this message:
* Serving Flask app "app.py"
* Environment: production
WARNING: This is a development server. Do not use it in a production deployment.
Use a production WSGI server instead.
* Debug mode: off
Usage: flask run [OPTIONS]
Error: Could not import "app".
What am I doing wrong?
Edit: App structure:
website/
| - app.py
Upvotes: 1
Views: 9105
Reputation: 1
If you do not provide the correct path, Flask will not be able to import your app. Check if you are inside the right folder with
pwd
You might see something like (I use MacOS so it might appear differently on your end if you use another OS)
/Users/your_username/Desktop/current_file
If you are not at the correct file, app, you can add in the path for that file, say the website file is inside your current_file. Then:
export FLASK_APP=/Users/your_username/Desktop/current_file/website/app.py
Then do flask run
. Hope this helped!
Upvotes: 0
Reputation: 1
If you have configured a virtualenv for your project, you have to activate the virtualenv with this command
>>>env\scripts\activate
Then make sure you are in the same directory where your app.py is located then use this commands
env>>>Set FLASK_APP=app.py
env>>>Set FLASK_ENVIRONMENT=development
env>>>flask run
keep cracking **note if you are on linux use 'export' instead of 'set'
Upvotes: 0
Reputation: 4991
from flask import Flask
app = Flask(__name__)
@app.route('/')
def index():
return "hi"
if __name__ == '__main__':
app.run(host='0.0.0.0', port=30006, debug=True)
Run in the same directory where this code is placed.
python3 file_name.py
You can access it on
http://0.0.0.0:30006/
Upvotes: 1