CODEWITHSUNDEEP
c++arraysstringstrlen
Conian
Conian

Reputation: 3

how to find the length of the string on the array?

I'm trying to get the length of the string from a char array

My input is:alpha kian namikian and the output should be 5 4 8 but at the moment my output is 11 11 11 11 11 11 11 11 11 11 11 which is not what I'm trying to achieve.

int i,count;
char str[100];  
cout<<"enter string\n";
for(i=0;;i++)
{
    cin>>str[i];

    if(cin.get()=='\n')
    {
        count=i+1;
        break;
    }
}
for(i=0;i<count;i++)
{
    int len = strlen(str);
    cout<<len<<"\n";
}

Upvotes: 0

Views: 77

Answers (2)

adq
adq

Reputation: 184

You have a compilation error because you're trying to fit an array of strings as a parameter to strlen. In your code, str contains all the strings, so you have to use access operator [] just like you did when you were taking strings from standard input.

int len = strlen(str) becomes int len = strlen(str[i]) and that should fix the error.

EDIT:

It looks like you can't use strlen with strings. Use length() instead.

int len = str[i].length()

EDIT #2:

Adding full code for reference with output:

#include <iostream>
#include <string>

using namespace std;

int main()
{
    int i, count;
    string str[100];
    cout << "enter string\n";
    for (i = 0;; i++)
    {
        cin >> str[i];

        if (cin.get() == '\n')
        {
            count = i + 1;
            break;
        }
    }
    for (i = 0; i < count; i++)
    {
        int len = str[i].length();
        cout << len << "\n";
    }
}

Output:

enter string

alpha kian namikian

5

4

8

Upvotes: 1

Nikhil
Nikhil

Reputation: 308

You can use this approach using the vector type string and exit the storing of the strings if entered string is exit
I am using a temp variable to store the string at any index and output the corresponding length.

    int i;
    vector<string> str;
    cout << "Enter String\n";
    while(cin)
    {
        string temp;
        cin >> temp;
        if(temp == "exit")
            break;
        else
            str.push_back(temp);

    }
    int n= str.size();
    for(i = 0; i< n; i++)
    {
        string temp = str[i];
        int len = temp.length();
        cout << len << endl;
    }

Upvotes: 0

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