CODEWITHSUNDEEP
pythonregexpython-3.xstringparsing
1Mangomaster1
1Mangomaster1

Reputation: 388

Python Split a String using more than one character while still keeping that character

I've seen many solutions using re.split but it doesn't solve my problem. I want to be able to split my string and keep some of the characters within the list... Hard to explain but here is an example:

Text: 

'print("hello world");'

the result I want:

["print", "(", "\"", "hello", "world", "\"", ")", ";"]

Things like re.split would give me:

["print", "hello", "world"]

How can I get the wanted result?

Upvotes: 2

Views: 118

Answers (2)

Ch3steR
Ch3steR

Reputation: 20669

You can try this.

import re
text='print("hello world");'
parsed=re.findall(r'(\w+|[^a-zA-Z\s])',text)
print(parsed)
#['print', '(', '"', 'hello', 'world', '"', ')', ';']

\w+ - To capture every word.

[^a-zA-Z\s] - To capture everything not in [a-zA-Z] and which is not a space.

EDIT: When you want to capture numbers and floats use this re expression \d+\.\d+|\d+|\w+|[^a-zA-Z\s]

\d+ - To capture numbers \d+\.\d+ - To capture floats.

a='print("hello world",[1,2,3,4,3.15]);'
print(re.findall('\d+\.\d+|\d+|\w+|[^a-zA-Z\s]',a)
#['print', '(', '"', 'hello', 'world', '"', ',', '[', '1', ',', '2', ',', '3', ',', '4', ',', '3.15', ']', ')', ';']

Upvotes: 6

theletz
theletz

Reputation: 1805

Try this:

import re
re.findall(r"[A-Za-z@#]+|\S", 'print("hello world");')

Out[19]: ['print', '(', '"', 'hello', 'world', '"', ')', ';']

Upvotes: 3

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