Reputation: 15
I am trying to display value in combobox using MySQL in vb.net. Right now the problem that I am facing is that combobox is not displaying values from MySQL. I have the below code:
MySqlConn = New MySqlConnection
MySqlConn.ConnectionString = "server=localhost;userid=root;password=root;database=s974_db"
Try
MySqlConn.Open()
Label21.Text = "DB Connection Successful"
Dim Query As String
Query = "select * from s974_db.processors where Name='" & ComboBox1.Text & "'"
COMMAND = New MySqlCommand(Query, MySqlConn)
READER = COMMAND.ExecuteReader
While READER.Read
Label10.Text = READER.GetDouble("Price")
End While
MySqlConn.Close()
Catch ex As MySqlException
MessageBox.Show(ex.Message)
Finally
MySqlConn.Dispose()
End Try
However, using the above code Combobox1.Text returns nothing but if I use below code which has a different query it works:
MySqlConn = New MySqlConnection
MySqlConn.ConnectionString = "server=localhost;userid=root;password=root;database=s974_db"
Try
MySqlConn.Open()
Label21.Text = "DB Connection Successful"
Dim Query As String
Query = "select * from s974_db.processors"
COMMAND = New MySqlCommand(Query, MySqlConn)
READER = COMMAND.ExecuteReader
While READER.Read
Dim sName = READER.GetString("Name")
ComboBox1.Items.Add(sName)
End While
MySqlConn.Close()
Catch ex As MySqlException
MessageBox.Show(ex.Message)
Finally
MySqlConn.Dispose()
End Try
Could someone please check and let me know what could be the issue? Thanks!
Upvotes: 1
Views: 579
Reputation: 49373
so the highlights as i mentioned them in the comments
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
' You need only to open aconnection once
MySqlConn = New MySqlConnection
MySqlConn.ConnectionString = "server=localhost;userid=root;password=root;database=s974_db"
Try
MySqlConn.Open()
Label21.Text = "db connection successful"
'First load both Combobox
Dim query As String
query = "select * from s974_db.processors"
COMMAND = New MySqlCommand(query, MySqlConn)
READER = COMMAND.ExecuteReader
While READER.Read
Dim sname = READER.GetString("name")
ComboBox1.Items.Add(sname)
ComboBox2.Items.Add(sname)
End While
Catch ex As MySqlException
MessageBox.Show(ex.Message)
Finally
End Try
End Sub
Private Sub Form1_Closing(ByVal sender As Object, ByVal e As EventArgs) Handles MyBase.Closing
Try
MySqlConn.Close()
MySqlConn.Dispose()
Catch ex As Exception
End Try
End Sub
ANd now the Comboboxes
Private Sub ComboBox1_SelectedIndexChanged(ByVal sender As Object, ByVal e As EventArgs) Handles ComboBox1.SelectedIndexChanged
'Only when there is a item selected , ask for data
If ComboBox1.SelectedIndex > -1 Then
Try
Dim Query As String
Query = "select * from s974_db.processors where Name='" & ComboBox1.Text & "'"
COMMAND = New MySqlCommand(Query, MySqlConn)
READER = COMMAND.ExecuteReader
While READER.Read
Label11.Text = READER.GetDouble("Price")
End While
Catch ex As MySqlException
MessageBox.Show(ex.Message)
Finally
End Try
End If
End Sub
Private Sub ComboBox2_SelectedIndexChanged(sender As Object, e As EventArgs) Handles ComboBox2.SelectedIndexChanged
If ComboBox2.SelectedIndex > -1 Then
Try
Dim Query As String
Query = "select * from s974_db.processors where Name='" & ComboBox1.Text & "'"
COMMAND = New MySqlCommand(Query, MySqlConn)
READER = COMMAND.ExecuteReader
While READER.Read
Label10.Text = READER.GetDouble("Price")
End While
Catch ex As MySqlException
MessageBox.Show(ex.Message)
Finally
End Try
End If
End Sub
This is exactly as i described on Form_load you fill both comboboxes
When you now change one of the comboxes one of the label change too.
Sometimes you have to update the Element to see a change
in that case you write at the end of the loop
Label10.Update()
Upvotes: 1
Reputation: 15081
Starting at the top... Keep your database objects local to the method where they are used. (Not Form level variables) You can make the connection string a class level string variable. This is the only way you can ensure that they are closed and disposed.
Using...End Using
blocks will close and dispose your database objects even if there is an error. The constructor of the connection takes the connection string. Connections are precious objects. Don't open the connection until directly before the .Execute
method and close it as soon as possible.
It doesn't make much sense that the user could select an item from ComboBox1
before the Form.Load
.
In general, we don't want to download anymore data than necessary and we want to hit the database as little as possible. In the Form.Load
we bind the combobox to a data table that contains the name and price fields, setting the display and value members. Now, whenever the user picks a name in the combo we can retrieve the price without connecting to the database again.
I noticed that you were using Val
in another event. This is an old VB6 method that can give you unexpected results. .Net and vb.net have all sorts of ways to get numbers out of strings that are faster and more reliable. CInt
, .TryParse
, .Parse
, CType
, Convert.To
etc.
Public Class Form1
Private ConString As String = "server=localhost;userid=root;password=root;database=s974_db"
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
'Fill combobox
Dim dt As New DataTable
Using cn As New MySqlConnection(ConString),
cmd As New MySqlCommand("select Name, Price from processors;", cn)
cn.Open()
dt.Load(cmd.ExecuteReader)
End Using 'Closes and disposes both connection and command
ComboBox1.DataSource = dt
ComboBox1.DisplayMember = "Name"
ComboBox1.ValueMember = "Price"
End Sub
Private Sub ComboBox1_SelectionChangeCommitted(sender As Object, e As EventArgs) Handles ComboBox1.SelectionChangeCommitted
Label10.Text = ComboBox1.SelectedValue.ToString
ClearLabels()
End Sub
Private Sub ClearLabels()
Label11.Text = ""
Label12.Text = ""
Label13.Text = ""
Label14.Text = ""
Label15.Text = ""
Label16.Text = ""
Label17.Text = ""
Label18.Text = ""
Label19.Text = ""
Label20.Text = ""
End Sub
End Class
Upvotes: 1