CODEWITHSUNDEEP
python
laxman
laxman

Reputation: 2110

Inconsistency in printing tuples in python

I have just started to learn python and following the docs on tuples, I came across this snippet,

>>> empty = ()
>>> singleton = 'hello',    # <-- note trailing comma
>>> len(empty)
0
>>> len(singleton)
1
>>> singleton
('hello',)

Following this I ran following snippet,

>>> foo=1,2,3,
>>> len(foo)
3
>>> foo
(1, 2, 3)

Why does singleton prints with an trailing comma , where as foo seems to trim it ?

Upvotes: 2

Views: 72

Answers (2)

Sayandip Dutta
Sayandip Dutta

Reputation: 15872

Beacause ("Hello") is not a tuple, it is same as "Hello".

>>> ("Hello")
'Hello'

in order to distinguish tuple with single element from a simple expression in () a , is necessary. Whereas (1,2,3) is clearly a collection of items, and as they are enclosed by () it can easily be inferred as a tuple, hence no need for a trailing ,.

Upvotes: 4

Tony
Tony

Reputation: 1

because you define variable"singleton" as ("hello",), you don't need comma to end it, and for "foo", you define it, so it shows as what you defined

Upvotes: 0

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