CODEWITHSUNDEEP
python
Kabera David
Kabera David

Reputation: 19

how to create a python program to make passwords using for and while

Hello i am trying to create a small code that receives password attempts for a number of times (3) , and if the password is wrong , the user can't try again .

can you please tell me why my code is not giving me the expected results i want?

the results it is giving me is a loop that never ends to ask for a try again ; while te results i desire is a loop that ends after 3 trials only . "i would love to keep in the while loop"

thank you very much

my code is 

password=''    
for i in range(1,3):
        if i<3:
           while password!='daniel':
                    password=input("enter the password:")
                    if password=="daniel":
                        print('your logged in ')
                    else:
                        print('try again ')
        else:
            print("number of trials done")

`

Upvotes: 1

Views: 406

Answers (5)

Ratnesh
Ratnesh

Reputation: 1700

for i in range(0,3):
    if i<3:
        password = input("enter the password:\n")
        if password=="daniel":
            print('your logged in ')
            break
        else:
            print('try again ')
            continue
    else:
        print("number of trials done")

Or

password=''
i = flag = 0
while password!='daniel'and  i<3:
    password=input("enter the password:\n")
    if password=="daniel":
        print('your logged in ')
        flag=1
    else:
        print('try again ')
    i +=1

if flag==0:
    print("number of trials done")

Upvotes: 0

Henok Teklu
Henok Teklu

Reputation: 538

The first problem with you code is you are using password with out intializing it. second the while loop will run forever unless the correct password is given. third even with the correct password given the while loop has a chance to restart for another 2 rounds

Here is an alternative

for trial in range(3):
    password=input("enter the password:")
    if password=="daniel":
        print('your logged in ')
        break
    elif trial == 2:
        print("number of trials done")
    else:
        print('try again ')
    trial = trial + 1

Upvotes: 0

Seif El-Din Sweilam
Seif El-Din Sweilam

Reputation: 274

Using both for loop and nested while loop makes the number of trials has no end. In addition, you should assign the variable password before you add it to the condition, or you can use while True and break instead.

counter = 0
while True:
    if counter < 3:
        counter += 1
        password = input('Enter the password: ')
        if password == 'daniel':
            print("You're logged in")
            break
        else:
            print('Try again')
    else:
        print('Number of trials is done. Please try again later.')
        break

Or you can do it using for loop.

for i in range(0,4):
    if i < 3:
        password = input('Enter the password: ')
        if password == 'daniel':
            print("You're logged in")
            break
        else:
            print('Try again')
    else:
        print('Number of trials is done. Please try again later.')
        break

Upvotes: 0

DarrylG
DarrylG

Reputation: 17156

for i in range(3):
  password=input("enter the password:")
  if password=="daniel":
      print('your logged in ')
      break
  elif i < 2:
      print('try again ')
else:
  print('Number trials exceeded')

Upvotes: 1

ba5h
ba5h

Reputation: 97

When you run this code you should get the error: NameError: name 'password' is not defined. This is because Python runs through your code line by line, and when it gets to the line while password!='daniel' it has no idea what password is because it hasn't yet been told, and so just stops running.

To fix errors like this you just need to first tell Python that password is going to be a variable which will store text. You can initialise the variable with empty text like so: password='', this must be put anywhere before the line that causes the error.

Upvotes: 1

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