Reputation: 7403
I really just want to pass an argument via docker run
My Dockerfile:
FROM python:3
# set a directory for the app
WORKDIR /usr/src/app
# copy all the files to the container
COPY . .
# install dependencies
RUN pip install --no-cache-dir -r requirements.txt
# tell the port number the container should expose
EXPOSE 5000
# run the command
CMD ["python", "./app.py"]
My python file:
import sys
print(sys.argv)
I tried:
docker run myimage foo
I got an error:
flask-app git:(master) ✗ docker run myimage foo
docker: Error response from daemon: OCI runtime create failed: container_linux.go:346: starting container process caused "exec: \"foo\": executable file not found in $PATH": unknown.
ERRO[0000] error waiting for container: context canceled
Upvotes: 1
Views: 437
Reputation: 1864
When you write foo at the end of your docker run command then you overwrite whole command. Therefore instead of
python app.py
you call
foo
Proper way of calling your script with arguments is:
docker run myimage python app.py foo
Alternatively you may use ENTRYPOINT instead of CMD and then your docker run command may contain just foo after image name
Dockerfile:
FROM python:3
# set a directory for the app
WORKDIR /usr/src/app
# copy all the files to the container
COPY app.py .
# run the command
ENTRYPOINT ["python", "./app.py"]
calling it:
docker run myimage foo
Upvotes: 2