CODEWITHSUNDEEP
phpjson
Kirk Ouimet
Kirk Ouimet

Reputation: 28364

Fastest way to check if a string is JSON in PHP?

I need a really, really fast method of checking if a string is JSON or not. I feel like this is not the best way:

function isJson($string) {
    return ((is_string($string) &&
            (is_object(json_decode($string)) ||
            is_array(json_decode($string))))) ? true : false;
}

Any performance enthusiasts out there want to improve this method?

Upvotes: 556

Views: 593829

Answers (28)

jcmargentina
jcmargentina

Reputation: 321

The RFC for the json_validate() function is implemented and part of PHP 8.3.

This method will be the fastest and most efficient way to achieve what the question is asking for.

github - implementation code

rfc - of json_validate()

Upvotes: 6

Henrik P. Hessel
Henrik P. Hessel

Reputation: 36617

function isJson($string) {
   json_decode($string);
   return json_last_error() === JSON_ERROR_NONE;
}

PHP >= 8.3 solution:

use json_validate() built-in function

Upvotes: 795

upful
upful

Reputation: 960

PHP 8.3

Native PHP function

json_validate(string $json, int $depth = 512, int $flags = 0): bool

https://wiki.php.net/rfc/json_validate

PHP < 8.3

A method that provides similar results to json_validate() above

function is_json($string) {
  return is_numeric($string)
    || in_array($string, ['null', 'true', 'false']
    || ( is_bool($string) && $string )
    || (
      !empty($string) 
      && is_string($string) 
      && is_array(json_decode($string, true)) 
      && json_last_error() === JSON_ERROR_NONE
    );
}

Sometimes it can be helpful to see if the JSON object has data, either an object or array

function has_json_data($string) {
  return !empty($string) 
    && is_string($string) 
    && is_array($array = json_decode($string, true)) 
    && !empty($array) 
    && json_last_error() === JSON_ERROR_NONE;
}

Upvotes: 31

Philipp
Philipp

Reputation: 11361

We first perform some type checks and string comparisons before attempting to decode the JSON string. This gives us the best performance because json_decode() can be slow.

/**
 * Returns true, when the given parameter is a valid JSON string.
 */
function is_json( $value ) {
    // Numeric strings are always valid JSON.
    if ( is_numeric( $value ) ) { return true; }

    // A non-string value can never be a JSON string.
    if ( ! is_string( $value ) ) { return false; }

    // Any non-numeric JSON string must be longer than 2 characters.
    if ( strlen( $value ) < 2 ) { return false; }

    // "null" is valid JSON string.
    if ( 'null' === $value ) { return true; }

    // "true" and "false" are valid JSON strings.
    if ( 'true' === $value ) { return true; }
    if ( 'false' === $value ) { return true; }

    // Any other JSON string has to be wrapped in {}, [] or "".
    if ( '{' != $value[0] && '[' != $value[0] && '"' != $value[0] ) { return false; }

    // Verify that the trailing character matches the first character.
    $last_char = $value[strlen($value) -1];
    if ( '{' == $value[0] && '}' != $last_char ) { return false; }
    if ( '[' == $value[0] && ']' != $last_char ) { return false; }
    if ( '"' == $value[0] && '"' != $last_char ) { return false; }

    // See if the string contents are valid JSON.
    return null !== json_decode( $value );
}

Extra: Use this logic to safely double-decode JSON

This function uses the same logic but either returns the decoded JSON object or the original value.

I use this function in a parser that recursively decodes a complex object. Some attributes might be decoded already by an earlier iteration. That function recognizes this and does not attempt to double decode the value again.

/**
 * Tests, if the given $value parameter is a JSON string.
 * When it is a valid JSON value, the decoded value is returned.
 * When the value is no JSON value (i.e. it was decoded already), then 
 * the original value is returned.
 */
function get_data( $value, $as_object = false ) {
    if ( is_numeric( $value ) ) { return 0 + $value; }
    if ( ! is_string( $value ) ) { return $value; }
    if ( strlen( $value ) < 2 ) { return $value; }
    if ( 'null' === $value ) { return null; }
    if ( 'true' === $value ) { return true; }
    if ( 'false' === $value ) { return false; }
    if ( '{' != $value[0] && '[' != $value[0] && '"' != $value[0] ) { return $value; }

    $json_data = json_decode( $value, $as_object );
    if ( is_null( $json_data ) ) { return $value; }
    return $json_data;
}

Note: When passing a non-string to any of the other solution in this SO question, you will get dramatically degraded performance + wrong return values (or even fatal errors). This code is bulletproof and highly performant.

Upvotes: 36

Ion Bazan
Ion Bazan

Reputation: 838

While PHP 8.3 which is still in development, will come with new memory-efficient json_validate() function, you can use it with older PHP versions (7.1 and newer) thanks to amazing Symfony Polyfill component.

Simply add following package to your project:

composer require symfony/polyfill-php83

and use it in your application:

if (json_validate($data)) {
  // do sometihng
}

Thanks to this approach, you can use new PHP features in older applications and migrate to PHP 8.3 without any code changes in the future as your code will automatically use the built-in function when it's available.

Upvotes: 8

Rounin
Rounin

Reputation: 29463

I found this question after coming across something similar in my work, yesterday. My solution in the end was a hybrid of some of the approaches above:

function is_JSON($string) {

  return (is_null(json_decode($string))) ? FALSE : TRUE;
}

Upvotes: 17

Madan Sapkota
Madan Sapkota

Reputation: 26071

Answer to the Question

The function json_last_error returns the last error occurred during the JSON encoding and decoding. So the fastest way to check the valid JSON is

// decode the JSON data
// set second parameter boolean TRUE for associative array output.
$result = json_decode($json);

if (json_last_error() === JSON_ERROR_NONE) {
    // JSON is valid
}

// OR this is equivalent

if (json_last_error() === 0) {
    // JSON is valid
}

Note that json_last_error is supported in PHP >= 5.3.0 only.

Full program to check the exact ERROR

It is always good to know the exact error during the development time. Here is full program to check the exact error based on PHP docs.

function json_validate($string)
{
    // decode the JSON data
    $result = json_decode($string);

    // switch and check possible JSON errors
    switch (json_last_error()) {
        case JSON_ERROR_NONE:
            $error = ''; // JSON is valid // No error has occurred
            break;
        case JSON_ERROR_DEPTH:
            $error = 'The maximum stack depth has been exceeded.';
            break;
        case JSON_ERROR_STATE_MISMATCH:
            $error = 'Invalid or malformed JSON.';
            break;
        case JSON_ERROR_CTRL_CHAR:
            $error = 'Control character error, possibly incorrectly encoded.';
            break;
        case JSON_ERROR_SYNTAX:
            $error = 'Syntax error, malformed JSON.';
            break;
        // PHP >= 5.3.3
        case JSON_ERROR_UTF8:
            $error = 'Malformed UTF-8 characters, possibly incorrectly encoded.';
            break;
        // PHP >= 5.5.0
        case JSON_ERROR_RECURSION:
            $error = 'One or more recursive references in the value to be encoded.';
            break;
        // PHP >= 5.5.0
        case JSON_ERROR_INF_OR_NAN:
            $error = 'One or more NAN or INF values in the value to be encoded.';
            break;
        case JSON_ERROR_UNSUPPORTED_TYPE:
            $error = 'A value of a type that cannot be encoded was given.';
            break;
        default:
            $error = 'Unknown JSON error occured.';
            break;
    }

    if ($error !== '') {
        // throw the Exception or exit // or whatever :)
        exit($error);
    }

    // everything is OK
    return $result;
}

Testing with Valid JSON INPUT

$json = '[{"user_id":13,"username":"stack"},{"user_id":14,"username":"over"}]';
$output = json_validate($json);
print_r($output);

Valid OUTPUT

Array
(
    [0] => stdClass Object
        (
            [user_id] => 13
            [username] => stack
        )

    [1] => stdClass Object
        (
            [user_id] => 14
            [username] => over
        )
)

Testing with invalid JSON

$json = '{background-color:yellow;color:#000;padding:10px;width:650px;}';
$output = json_validate($json);
print_r($output);

Invalid OUTPUT

Syntax error, malformed JSON.

Extra note for (PHP >= 5.2 && PHP < 5.3.0)

Since json_last_error is not supported in PHP 5.2, you can check if the encoding or decoding returns boolean FALSE. Here is an example

// decode the JSON data
$result = json_decode($json);
if ($result === FALSE) {
    // JSON is invalid
}

Upvotes: 238

milad nazari
milad nazari

Reputation: 403

function isJson($string) {
    $obj = json_decode($string);
    return json_last_error() === JSON_ERROR_NONE && gettype($obj ) == "object";
}

this works and doesn't return true for numbers

new update

The above solution does not have good performance if the JSON is long and you don't need to use $obj

if you just want check, it's better to use below function

function isJson($string) {
    if(is_numeric($string)) return false;
    json_decode($string);
    return json_last_error() === JSON_ERROR_NONE;
}

Upvotes: 1

Matthew Anderson
Matthew Anderson

Reputation: 444

Using PHPBench with the following class, the below results were achieved:

<?php

declare(strict_types=1);

/**
 * @Revs(1000)
 * @Iterations(100)
 */
class BenchmarkJson
{
    public function benchCatchValid(): bool
    {
        $validJson = '{"validJson":true}';
        try {
            json_decode($validJson, true, 512, JSON_THROW_ON_ERROR);
            return true;
        } catch(\JsonException $exception) {}
        return false;
    }

    public function benchCatchInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        try {
            json_decode($invalidJson, true, 512, JSON_THROW_ON_ERROR);
            return true;
        } catch(\JsonException $exception) {}
        return false;
    }

    public function benchLastErrorValid(): bool
    {
        $validJson = '{"validJson":true}';
        json_decode($validJson, true);
        return (json_last_error() === JSON_ERROR_NONE);
    }

    public function benchLastErrorInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        json_decode($invalidJson, true);
        return (json_last_error() === JSON_ERROR_NONE);
    }

    public function benchNullValid(): bool
    {
        $validJson = '{"validJson":true}';
        return (json_decode($validJson, true) !== null);
    }

    public function benchNullInvalid(): bool
    {
        $invalidJson = '{"invalidJson"';
        return (json_decode($invalidJson, true) !== null);
    }
}


6 subjects, 600 iterations, 6,000 revs, 0 rejects, 0 failures, 0 warnings
(best [mean mode] worst) = 0.714 [1.203 1.175] 1.073 (μs)
⅀T: 721.504μs μSD/r 0.089μs μRSD/r: 7.270%
suite: 1343ab9a3590de6065bc0bc6eeb344c9f6eba642, date: 2020-01-21, stime: 12:50:14
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| benchmark     | subject               | set | revs | its | mem_peak   | best    | mean    | mode    | worst   | stdev   | rstdev | diff  |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| BenchmarkJson | benchCatchValid       | 0   | 1000 | 100 | 2,980,168b | 0.954μs | 1.032μs | 1.016μs | 1.428μs | 0.062μs | 6.04%  | 1.33x |
| BenchmarkJson | benchCatchInvalid     | 0   | 1000 | 100 | 2,980,184b | 2.033μs | 2.228μs | 2.166μs | 3.001μs | 0.168μs | 7.55%  | 2.88x |
| BenchmarkJson | benchLastErrorValid   | 0   | 1000 | 100 | 2,980,184b | 1.076μs | 1.195μs | 1.169μs | 1.616μs | 0.083μs | 6.97%  | 1.54x |
| BenchmarkJson | benchLastErrorInvalid | 0   | 1000 | 100 | 2,980,184b | 0.785μs | 0.861μs | 0.863μs | 1.132μs | 0.056μs | 6.54%  | 1.11x |
| BenchmarkJson | benchNullValid        | 0   | 1000 | 100 | 2,980,168b | 0.985μs | 1.124μs | 1.077μs | 1.731μs | 0.114μs | 10.15% | 1.45x |
| BenchmarkJson | benchNullInvalid      | 0   | 1000 | 100 | 2,980,184b | 0.714μs | 0.775μs | 0.759μs | 1.073μs | 0.049μs | 6.36%  | 1.00x |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+

Conclusion: The fastest way to check if json is valid is to return json_decode($json, true) !== null).

Upvotes: 14

user10012
user10012

Reputation: 715

This is what I recommend

if (!in_array(substr($string, 0, 1), ['{', '[']) || !in_array(substr($string, -1), ['}', ']'])) {
  return false;
} else {
  json_decode($string);
  return (json_last_error() === JSON_ERROR_NONE);
}

Upvotes: 0

user1653711
user1653711

Reputation: 1177

All you really need to do is this...

if (is_object(json_decode($MyJSONArray))) 
{ 
    ... do something ...
}

This request does not require a separate function even. Just wrap is_object around json_decode and move on. Seems this solution has people putting way too much thought into it.

Upvotes: 107

user11995521
user11995521

Reputation: 

//Tested thoroughly, Should do the job:
public static function is_json(string $json):bool
{
    json_decode($json);
    if (json_last_error() === JSON_ERROR_NONE) {
        return true;
    }
    return false;
}

Upvotes: 6

Lewis Donovan
Lewis Donovan

Reputation: 1127

This will do it:

function isJson($string) {
    $decoded = json_decode($string); // decode our JSON string
    if ( !is_object($decoded) && !is_array($decoded) ) {
        /*
        If our string doesn't produce an object or array
        it's invalid, so we should return false
        */
        return false;
    }
    /*
    If the following line resolves to true, then there was
    no error and our JSON is valid, so we return true.
    Otherwise it isn't, so we return false.
    */
    return (json_last_error() == JSON_ERROR_NONE);
}

if ( isJson($someJsonString) ) {
    echo "valid JSON";
} else {
    echo "not valid JSON";
}

As shown in other answers, json_last_error() returns any error from our last json_decode(). However there are some edge use cases where this function alone is not comprehensive enough. For example, if you json_decode() an integer (eg: 123), or a string of numbers with no spaces or other characters (eg: "123"), the json_last_error() function will not catch an error.

To combat this, I've added an extra step that ensures the result of our json_decode() is either an object or an array. If it's not, then we return false.

To see this in action, check these two examples:

Upvotes: 14

Jack
Jack

Reputation: 302

Hi here's a little snippet from my library, in this first condition I'm just checking if the data is json then return it if correctly decoded, please note the substr usage for performance ( I haven't seen yet any json file not begining neither by { or [

$input=trim($input);
if ((substr($input, 0, 1) == '{' && substr($input, -1) == '}') or (substr($input, 0, 1) == '[' && substr($input, -1) == ']')) {
    $output = json_decode($input, 1);
    if (in_array(gettype($output),['object','array'])) {
        #then it's definitely JSON
    }
}

Upvotes: 2

Mohammad Mursaleen
Mohammad Mursaleen

Reputation: 603

The simplest and fastest way that I use is following;

$json_array = json_decode( $raw_json , true );

if( $json_array == NULL )   //check if it was invalid json string
    die ('Invalid');  // Invalid JSON error

 // you can execute some else condition over here in case of valid JSON

It is because json_decode() returns NULL if the entered string is not json or invalid json.


Simple function to validate JSON

If you have to validate your JSON in multiple places, you can always use the following function.

function is_valid_json( $raw_json ){
    return ( json_decode( $raw_json , true ) == NULL ) ? false : true ; // Yes! thats it.
}

In the above function, you will get true in return if it is a valid JSON.

Upvotes: 29

Tinh Dang
Tinh Dang

Reputation: 478

Should be something like this:

 function isJson($string)
 {
    // 1. Speed up the checking & prevent exception throw when non string is passed
    if (is_numeric($string) ||
        !is_string($string) ||
        !$string) {
        return false;
    }

    $cleaned_str = trim($string);
    if (!$cleaned_str || !in_array($cleaned_str[0], ['{', '['])) {
        return false;
    }

    // 2. Actual checking
    $str = json_decode($string);
    return (json_last_error() == JSON_ERROR_NONE) && $str && $str != $string;
}

UnitTest

public function testIsJson()
{
    $non_json_values = [
        "12",
        0,
        1,
        12,
        -1,
        '',
        null,
        0.1,
        '.',
        "''",
        true,
        false,
        [],
        '""',
        '[]',
        '   {',
        '   [',
    ];

   $json_values = [
        '{}',
        '{"foo": "bar"}',
        '[{}]',
        '  {}',
        ' {}  '
    ];

   foreach ($non_json_values as $non_json_value) {
        $is_json = isJson($non_json_value);
        $this->assertFalse($is_json);
    }

    foreach ($json_values as $json_value) {
        $is_json = isJson($json_value);
        $this->assertTrue($is_json);
    }
}

Upvotes: 2

Greco Jonathan
Greco Jonathan

Reputation: 2524

I've tried some of those solution but nothing was working for me. I try this simple thing :

$isJson = json_decode($myJSON);

if ($isJson instanceof \stdClass || is_array($isJson)) {
   echo("it's JSON confirmed");
} else {
   echo("nope");
}

I think it's a fine solutiuon since JSON decode without the second parameter give an object.

EDIT : If you know what will be the input, you can adapt this code to your needs. In my case I know I have a Json wich begin by "{", so i don't need to check if it's an array.

Upvotes: 2

Cyril
Cyril

Reputation: 3148

This will return true if your string represents a json array or object:

function isJson($str) {
    $json = json_decode($str);
    return $json && $str != $json;
}

It rejects json strings that only contains a number, string or boolean, although those strings are technically valid json.

var_dump(isJson('{"a":5}')); // bool(true)
var_dump(isJson('[1,2,3]')); // bool(true)
var_dump(isJson('1')); // bool(false)
var_dump(isJson('1.5')); // bool(false)
var_dump(isJson('true')); // bool(false)
var_dump(isJson('false')); // bool(false)
var_dump(isJson('null')); // bool(false)
var_dump(isJson('hello')); // bool(false)
var_dump(isJson('')); // bool(false)

It is the shortest way I can come up with.

Upvotes: 72

Parsa
Parsa

Reputation: 644

in GuzzleHttp:

/**
 * Wrapper for json_decode that throws when an error occurs.
 *
 * @param string $json    JSON data to parse
 * @param bool $assoc     When true, returned objects will be converted
 *                        into associative arrays.
 * @param int    $depth   User specified recursion depth.
 * @param int    $options Bitmask of JSON decode options.
 *
 * @return mixed
 * @throws \InvalidArgumentException if the JSON cannot be decoded.
 * @link http://www.php.net/manual/en/function.json-decode.php
 */
function json_decode($json, $assoc = false, $depth = 512, $options = 0)
{
    $data = \json_decode($json, $assoc, $depth, $options);
    if (JSON_ERROR_NONE !== json_last_error()) {
        throw new \InvalidArgumentException(
            'json_decode error: ' . json_last_error_msg());
    }

    return $data;
}

/**
 * Wrapper for JSON encoding that throws when an error occurs.
 *
 * @param mixed $value   The value being encoded
 * @param int    $options JSON encode option bitmask
 * @param int    $depth   Set the maximum depth. Must be greater than zero.
 *
 * @return string
 * @throws \InvalidArgumentException if the JSON cannot be encoded.
 * @link http://www.php.net/manual/en/function.json-encode.php
 */
function json_encode($value, $options = 0, $depth = 512)
{
    $json = \json_encode($value, $options, $depth);
    if (JSON_ERROR_NONE !== json_last_error()) {
        throw new \InvalidArgumentException(
            'json_encode error: ' . json_last_error_msg());
    }

    return $json;
}

Upvotes: 6

Rameez Rami
Rameez Rami

Reputation: 5728

Easy method is to check the json result..

$result = @json_decode($json,true);
    if (is_array($result)) {
        echo 'JSON is valid';
    }else{
        echo 'JSON is not valid';
    }

Upvotes: 9

Sergey Onishchenko
Sergey Onishchenko

Reputation: 7851

We need to check if passed string is not numeric because in this case json_decode raises no error.

function isJson($str) {
    $result = false;
    if (!preg_match("/^\d+$/", trim($str))) {
        json_decode($str);
        $result = (json_last_error() == JSON_ERROR_NONE);
    }

    return $result;
}

Upvotes: 5

Robert Johnstone
Robert Johnstone

Reputation: 5371

Expanding on this answer How about the following:

<?php

    $json = '[{"user_id":13,"username":"stack"},{"user_id":14,"username":"over"}]';
    //$json = '12';

    function isJson($string) {
        json_decode($string);
        if(json_last_error() == JSON_ERROR_NONE) {
            if(substr($string,0,1) == '[' && substr($string,-1) == ']') { return TRUE; }
            else if(substr($string,0,1) == '{' && substr($string,-1) == '}') { return TRUE; }
            else { return FALSE; }
        }
    }

    echo isJson($json);
?>

Upvotes: 0

biziclop
biziclop

Reputation: 14596

Freshly-made function for PHP 5.2 compatibility, if you need the decoded data on success:

function try_json_decode( $json, & $success = null ){
  // non-strings may cause warnings
  if( !is_string( $json )){
    $success = false;
    return $json;
  }

  $data = json_decode( $json );

  // output arg
  $success =

    // non-null data: success!
    $data !==  null  ||

    // null data from 'null' json: success!
    $json === 'null' ||

    // null data from '  null  ' json padded with whitespaces: success!
    preg_match('/^\s*null\s*$/', $json );

  // return decoded or original data
  return $success ? $data : $json;
}

Usage:

$json_or_not = ...;

$data = try_json_decode( $json_or_not, $success );

if( $success )
     process_data( $data );
else what_the_hell_is_it( $data );

Some tests:

var_dump( try_json_decode( array(), $success ), $success );
// ret = array(0){}, $success == bool(false)

var_dump( try_json_decode( 123, $success ), $success );
// ret = int(123), $success == bool(false)

var_dump( try_json_decode('      ', $success ), $success );
// ret = string(6) "      ", $success == bool(false)

var_dump( try_json_decode( null, $success ), $success );
// ret = NULL, $success == bool(false)

var_dump( try_json_decode('null', $success ), $success );
// ret = NULL, $success == bool(true)

var_dump( try_json_decode('  null  ', $success ), $success );
// ret = NULL, $success == bool(true)

var_dump( try_json_decode('  true  ', $success ), $success );
// ret = bool(true), $success == bool(true)

var_dump( try_json_decode('  "hello"  ', $success ), $success );
// ret = string(5) "hello", $success == bool(true)

var_dump( try_json_decode('  {"a":123}  ', $success ), $success );
// ret = object(stdClass)#2 (1) { ["a"]=> int(123) }, $success == bool(true)

Upvotes: -2

mario
mario

Reputation: 145482

Using json_decode to "probe" it might not actually be the fastest way. If it's a deeply nested structure, then instantiating a lot of objects of arrays to just throw them away is a waste of memory and time.

So it might be faster to use preg_match and the RFC4627 regex to also ensure validity:

  // in JS:
  var my_JSON_object = !(/[^,:{}\[\]0-9.\-+Eaeflnr-u \n\r\t]/.test(
         text.replace(/"(\\.|[^"\\])*"/g, '')));

The same in PHP:

  return !preg_match('/[^,:{}\\[\\]0-9.\\-+Eaeflnr-u \\n\\r\\t]/',
       preg_replace('/"(\\.|[^"\\\\])*"/', '', $json_string));

Not enough of a performance enthusiast to bother with benchmarks here however.

Upvotes: 77

Ahad Ali
Ahad Ali

Reputation: 418

Earlier i was just checking for a null value, which was wrong actually.

    $data = "ahad";
    $r_data = json_decode($data);
    if($r_data){//json_decode will return null, which is the behavior we expect
        //success
    }

The above piece of code works fine with strings. However as soon as i provide number, it breaks up.for example.

    $data = "1213145";
    $r_data = json_decode($data);

    if($r_data){//json_decode will return 1213145, which is the behavior we don't expect
        //success
    }

To fix it what i did was very simple.

    $data = "ahad";
    $r_data = json_decode($data);

    if(($r_data != $data) && $r_data)
        print "Json success";
    else
        print "Json error";

Upvotes: 5

h0mayun
h0mayun

Reputation: 3601

Another simple way

function is_json($str)
{
    return is_array(json_decode($str,true));
}

Upvotes: 3

maxpower9000
maxpower9000

Reputation: 221

I don't know about performance or elegance of my solution, but it's what I'm using:

if (preg_match('/^[\[\{]\"/', $string)) {
    $aJson = json_decode($string, true);
    if (!is_null($aJson)) {
       ... do stuff here ...
    }
}

Since all my JSON encoded strings start with {" it suffices to test for this with a RegEx. I'm not at all fluent with RegEx, so there might be a better way to do this. Also: strpos() might be quicker.

Just trying to give in my tuppence worth.

P.S. Just updated the RegEx string to /^[\[\{]\"/ to also find JSON array strings. So it now looks for either [" or {" at the beginning of the string.

Upvotes: 1

ahmet alp balkan
ahmet alp balkan

Reputation: 45214

function is_json($str){ 
    return json_decode($str) != null;
}

http://tr.php.net/manual/en/function.json-decode.php return value is null when invalid encoding detected.

Upvotes: 25

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