CODEWITHSUNDEEP
pythonpython-3.xlistwhile-loop
leopardxpreload
leopardxpreload

Reputation: 768

How to run a while conditional which looks at a position of all lists in a nested list?

[Python 3.7]

I want to run a while() condition which looks at the 3rd position of all lists in a nested list:

example:

list = [[0,2,3,4], [4,3,2,5], [3,4,3,2]]

while list[:][2] != 2:    # ':' denoting all (I know its not correct)
    pass                  # AKA do something

I want to do this because in the code I am working on I have parts of a list that require deletion and I need to know when only a specific element is left.

Upvotes: 1

Views: 50

Answers (1)

miszcz2137
miszcz2137

Reputation: 914

For example:

while all((row[2] != 2 for row in list)):

or:

while any((row[2] != 2 for row in list)):

depending on what you really want.

Upvotes: 2

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