Reputation: 19
List<Dictionary<string, string>> firstList = new List<Dictionary<string, string>>();
Dictionary<string, string> dict = new Dictionary<string,string>();
dict.Add("name", "abc");
dict.Add("age", "22");
dict.Add("address", "xyz,aa");
dict.Add("contact", "111");
firstList .Add(dict);
Dictionary<string, string> dict2 = new Dictionary<string,string>();
dict2 .Add("name", "pqr");
dict2 .Add("age", "25");
dict2 .Add("address", "xxx,bb");
dict2 .Add("contact", "4222");
firstList .Add(dict2);
Dictionary<string, string> dict3 = new Dictionary<string,string>();
dict3 .Add("name", "aa");
dict3 .Add("age", "24");
dict3 .Add("address", "xxx,aa");
dict3 .Add("contact", "aaa");
firstList .Add(dict3);
return record where list doesn't not contains key = 'address' and name= 'aa'
Update :- return record where name= 'aa'
Upvotes: 0
Views: 1297
Reputation: 62488
Pretty simple with linq:
var result = firstList.Where(x => !(x.ContainsKey("address")
&& x.ContainsKey(name)
&& x["name"] == "aa")).ToList();
and if only one record is required back then use FirstOrDefault()
:
var result = firstList.Where(x => !(x.ContainsKey("address")
&& x.ContainsKey(name)
&& x["name"] == "aa")).FirstOrDefault();
Don't forget to add on top:
using System.Linq;
var result = firstList.Where(x =>
&& x.ContainsKey(name)
&& x["name"] != "aa")).FirstOrDefault();
Upvotes: 1