Reputation: 2869
I want to get the top value in each group based on ID_DATE
column from the following record. Group by ID_TOPIC
CREATE TABLE DA_TBL(
DATA_ID VARCHAR2(50),
REF_DESC VARCHAR2(50),
DATE_L DATE NOT NULL,
ID_TOPIC VARCHAR2(50),
ID_DATE NUMBER
);
INSERT all
INTO DA_TBL VALUES ('1','sample 1',CURRENT_TIMESTAMP, 'local', 1)
INTO DA_TBL VALUES ('2','sample 2',CURRENT_TIMESTAMP, 'tradition', 2)
INTO DA_TBL VALUES ('3','sample 2',CURRENT_TIMESTAMP, 'gospel', 3)
INTO DA_TBL VALUES ('4','sample 4',CURRENT_TIMESTAMP, 'local', 4)
INTO DA_TBL VALUES ('5','sample 5',CURRENT_TIMESTAMP, 'gospel', 5)
INTO DA_TBL VALUES ('6','sample 6',CURRENT_TIMESTAMP, 'tradition', 6)
INTO DA_TBL VALUES ('7','sample 7',CURRENT_TIMESTAMP, 'gospel', 7)
INTO DA_TBL VALUES ('8','sample 8',CURRENT_TIMESTAMP, 'local', 8)
INTO DA_TBL VALUES ('9','sample 9',CURRENT_TIMESTAMP, 'tradition', 9)
INTO DA_TBL VALUES ('10','sample 10',CURRENT_TIMESTAMP, 'local', 10)
INTO DA_TBL VALUES ('11','sample 11',CURRENT_TIMESTAMP, 'gospel', 11)
SELECT * FROM dual;
What I want is:
DATA_ID|REF_DESC |ID_TOPIC |ROWNUMBER|
-------|---------|---------|---------|
9 |sample 9 |tradition| 1|
10 |sample 10|local | 1|
11 |sample 11|gospel | 1|
What I get is:
DATA_ID|REF_DESC|ID_TOPIC |ROWNUMBER|
-------|--------|---------|---------|
9 |sample 9|tradition| 1|
8 |sample 8|local | 1|
7 |sample 7|gospel | 1|
What I have tried
SELECT *
FROM (SELECT DATA_ID, REF_DESC, ID_TOPIC
, ROW_NUMBER() OVER (PARTITION BY ID_TOPIC ORDER BY DATA_ID DESC) AS rownumber
FROM DA_TBL ORDER BY DATA_ID DESC)
WHERE rownumber = 1;
Upvotes: 2
Views: 103
Reputation: 1269443
I want to get the top value in each group based on ID_DATE
If so, why are you focusing on DATA_ID
?
The query you want is:
SELECT *
FROM (SELECT DATA_ID, REF_DESC, ID_TOPIC ,
ROW_NUMBER() OVER (PARTITION BY ID_TOPIC ORDER BY ID_DATE DESC) AS rownumber
FROM DA_TBL
)
WHERE rownumber = 1
ORDER BY TO_NUMBER(DATA_ID) DESC;
Here is a db<>fiddle.
Upvotes: 1
Reputation: 1300
Try the following query :
SELECT
t1.DATA_ID,
t1.REF_DESC,
t1.ID_TOPIC
FROM yourTable t1
JOIN (
SELECT
ID_TOPIC,
MAX(ID_DATE) AS maxIdDate
FROM yourTable
GROUP BY ID_TOPIC
) t2 ON t1.ID_TOPIC = t2.ID_TOPIC AND t1.ID_DATE = t2.maxIdDate
I think you used the wrong column in your query, so it should also work if you fix it this way :
SELECT
*
FROM (
SELECT
DATA_ID,
REF_DESC,
ID_TOPIC,
ROW_NUMBER() OVER (PARTITION BY ID_TOPIC ORDER BY ID_DATE DESC) AS rownumber
FROM DA_TBL
) t
WHERE rownumber = 1;
Upvotes: 1
Reputation: 37337
This is because you have varchar
datatype on DATA_ID
.
For correct ordering (you expect integer ordering, not a text order), you need to cast it:
ROW_NUMBER() OVER (PARTITION BY ID_TOPIC ORDER BY CAST(DATA_ID AS NUMBER) DESC)
Side note: datatypes in your tables are wrong - if you have an ID, it naturally should be stored as a number (unless you have some special requirements).
From what you posted, you store two ID columns as varchar
, it should be number
instead.
Upvotes: 1
Reputation: 142710
Your problem is DATA_ID
column's datatype. It is a string, and strings are sorted differently than numbers. 9 is "larger" than 10.
If you can, modify column's datatype to NUMBER
.
Or, apply TO_NUMBER
here:
ROW_NUMBER() OVER (PARTITION BY ID_TOPIC ORDER BY TO_NUMBER(DATA_ID) DESC)
------------------
here
This might not work if column contains alphanumeric values.
SQL> l
1 SELECT *
2 FROM (SELECT DATA_ID, REF_DESC, ID_TOPIC
3 , ROW_NUMBER() OVER (PARTITION BY ID_TOPIC ORDER BY to_number(DATA_ID) DESC) AS rownumber
4 FROM DA_TBL ORDER BY DATA_ID DESC)
5* WHERE rownumber = 1
SQL> /
DATA_ID REF_DESC ID_TOPIC ROWNUMBER
------- ---------- ---------- ----------
9 sample 9 tradition 1
11 sample 11 gospel 1
10 sample 10 local 1
SQL>
Upvotes: 2