Reputation: 21
I am inserting my data in a database with json_encoded. Now I want to search in "feature", but the result is not exactly true.
MySQL query:
select *
from `modul_69`
where `extmod` like '%"68":%'
and `extmod` like '%"4"%'
and `extmod` not like '%"4":%'
Results:
row1 data:
{"68":["1","4","7"],"67":["14"],"75":["28"]} - true
row2 data:
{"68":["59"],"67":["1","11","13"],"75":["3","4","5","27"]} - false
I want select only row1
by key:68
and value:4
Please help
Upvotes: 1
Views: 1233
Reputation: 15257
To find if the value '"4"'
is contained in the member '"68"'
, you can first extract the array using JSON_EXTRACT()
:
SELECT JSON_EXTRACT(m.extmod, '$."68"')
FROM modul_69 m;
This outputs
["1", "4", "7"]
["59"]
To search in a JSON array if it contains a specific value, you can use JSON_CONTAINS()
:
SELECT JSON_CONTAINS('["1", "4", "7"]', '"4"', '$'); -- output is 1
SELECT JSON_CONTAINS('["59"]', '"4"', '$'); -- output is 0
Now you can combine both functions to get the rows that contains the expected value :
Schema (MySQL v5.7)
CREATE TABLE modul_69
(
extmod JSON
);
INSERT INTO modul_69 VALUES ('{"68":["1","4","7"],"67":["14"],"75":["28"]}'), ('{"68":["59"],"67":["1","11","13"],"75":["3","4","5","27"]}');
Query #1
SELECT *
FROM modul_69 m
WHERE JSON_CONTAINS(JSON_EXTRACT(m.extmod, '$."68"'),
'"4"',
'$') = 1;
Output
| extmod |
| --------------------------------------------------- |
| {"67": ["14"], "68": ["1", "4", "7"], "75": ["28"]} |
Upvotes: 1
Reputation: 222652
Here is one way to do it using MySQL JSON functions, available since version 5.7:
select *
from t
where json_search(js -> '$."68"', 'one', '4') is not null
What this does is get the array that correspond to outer key '68'
(using ->
, which is a syntactic sugar for json_extract()
), and then search its content with json_search()
; if a non-null
value is returned, we have a match.
Upvotes: 2