Reputation: 1576
I have three tables - users, properties, devices.
users
id
name
properties
id
name
user_id
devices
id
name
property_id
How to define straight relationship to user model from devices model?
class Device extends Model
{
public function user()
{
return $this->....();
}
}
Is it possible to define such relation? Thanks.
Upvotes: 0
Views: 92
Reputation: 1576
I think I have found the solution, this is what I end up with.
class Device extends Model
{
public function user()
{
$instance = new User();
$instance->setTable('properties');
$query = $instance->newQuery();
return (new BelongsTo($query, $this, 'property_id', $instance->getKeyName(), 'property'))
->join('users', 'users.id', '=', 'properties.user_id')
->select(DB::raw('users.*')
);
}
}
Hope this will be of help for somebody.
Upvotes: 0
Reputation: 2087
Make sure to set all relation in other classes.
class Property extends Model
{
public function user()
{
return $this->belongsTo('App\User');
}
}
class Device extends Model
{
public function property()
{
return $this->belongsTo('App\Property');
}
public function user()
{
return $this->belongsTo('App\User', null, null, 'property');
}
}
You can provide a relation with in 4th parameter of belongsTo method.
Upvotes: 2
Reputation: 1
//user model
public function role()
{
return $this->belongsTo('App\Role');
}
public function employee()
{
return $this->hasMany('App\Employee');
}
//role model
public function users()
{
return $this->hasMany('App\User');
}
//employee model
public function users()
{
return $this->belongsTo('App\User');
}
//value show using tinker command in command promote
App\User::find(1)->employee;
App\User::find(1)->role;
Upvotes: 0