CODEWITHSUNDEEP
c#wpfwpf-controlsconsoleconsole-application
ale
ale

Reputation: 3421

How Start a window with Main() in Console Project.?

I have a console project, but now I need to put an user interface on. So I'm using the 3 tier model (presentation, business, access data).

In my method Main() I call to presentation layer (like app in Window form or Wpf), so, in the presentation layer is the interaction with user through CONSOLE.

Now I add a window called "UserInterface.xaml" in the presentation layer to use instead of console. Because should be with INTERFACE not console.

I have observed that in MainWindow the called is with MainWindow.Show();

But I don't know how to call my "UserInterface.xaml", because has no .Show() method.

This is my method Main:

public static void Main()
{
  MainWindow.Show(); // THIS IS WITH MainWindow.xaml
  UserInterface.???  // THIS IS MY CASE WITH UserInterface.xaml
}

So can somebody tell me how I can call my window from the Main method??

Upvotes: 1

Views: 2744

Answers (2)

Hans Passant
Hans Passant

Reputation: 941217

You definitely got started with the wrong project template. To make a WPF window visible and interactive, you have to follow the rules for a UI thread. Which includes marking the main thread of your app as an STA thread and pumping a message loop. Like this:

class Program {
    [STAThread]
    public static void Main() {
        var app = new Application();
        app.Run(new MainWindow());
    }
}

Beware that Application.Run() is a blocking call, it will not return until the user closes the main window. This is a rather inevitable consequence of the way Windows works.

Upvotes: 5

svick
svick

Reputation: 244757

Assuming UserInterface is really a window, this should work:

var window = new UserInterface();
window.Show();

Upvotes: 1

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