Reputation: 1137
How do I get a result with file names at the beginning and the total number of files? When I run the command line below, it only shows the number of files but not file names.
I would like to get the zip file name and the number of documents in zip. Thanks
Desired output:
IAD1.zip 30000 files
IAD2.zip 24000 files
IAD3.zip 32000 files
.....
Command line:
zipinfo IAD${count}.zip |grep ^-|wc -l >>TotalCount.txt
With the command above, the result shows the number of documents in zip files, but not file names:
30000
24000
32000
.....
Upvotes: 11
Views: 18703
Reputation: 2705
zipinfo -h <file name> | tr '\n' ':' | awk -F':' '{print $2 , $5 , "files"}'
explanation:
zipinfo -h
-- list header line. The archive name, actual size (in bytes) and total number of files is printed.
tr '\n' ':'
-- Replace new line with ":"
awk -F':' '{print $2 , $5 , "files"}'
-- Read file as ":" delimited and print 2nd and 5th field
Demo:
:>zipinfo test.zip
Archive: test.zip
Zip file size: 2798 bytes, number of entries: 7
-rw-r--r-- 3.0 unx 18 tx stor 20-Mar-10 13:00 file1.dat
-rw-r--r-- 3.0 unx 32 tx defN 20-Mar-10 13:00 file2.dat
-rw-r--r-- 3.0 unx 16 tx stor 20-Mar-10 12:26 file3.dat
-rw-r--r-- 3.0 unx 1073 tx defN 20-Mar-12 05:24 join1.txt
-rw-r--r-- 3.0 unx 114 tx defN 20-Mar-12 05:25 join2.txt
-rw-r--r-- 3.0 unx 254 tx defN 20-Mar-11 09:39 sample.txt
-rw-r--r-- 3.0 unx 1323 bx stor 20-Mar-14 09:14 test,zip.zip
7 files, 2830 bytes uncompressed, 1746 bytes compressed: 38.3%
:>zipinfo -h test.zip | tr '\n' ':' | awk -F':' '{print $2 , $5 , "files"}'
test.zip 7 files
Upvotes: 18
Reputation: 51
To list all the filenames in the ZIP file:
unzip -l <path/to/your/zipfile.zip>
This command lists all files in the ZIP archive along with some additional information (like file sizes and timestamps).
Use grep
to get specific file Like .txt
or .html
unzip -l <path/to/your/zipfile.zip> | grep html | wc -l
It's multiple extension files and you're only interested in the filenames and want to count them, you can use grep to filter and count the results
unzip -l <path/to/your/zipfile.zip> | grep -v '^Archive:' | grep -v '^--------' | grep -v '^ ' | grep -v ' files$' | wc -l
unzip -l path/to/your/zipfile.zip lists the contents of the ZIP file.
grep -v '^Archive:' removes the line starting with "Archive:".
grep -v '^--------' removes the separator lines.
grep -v '^ ' removes lines starting with a space, which are usually part of the summary.
grep -v ' files$' removes the final line that shows the total count and size (since we're counting them separately).
wc -l counts the number of lines, which corresponds to the number of files.
Upvotes: 0