CODEWITHSUNDEEP
pythonfunctiondictionarykeyreturn-value
user12469303
user12469303

Reputation:

Function to return values in dictionary

This is my dictionary:

seven_segment = {'0': {'a','c','d','e','b','f'},
                 '1': {'c','b'},
                 '2': {'a','d','e','b','g'},
                 '3': {'a','c','d','b','g'},
                 '4': {'g','c','f','b'},
                 '5': {'a','c','d','g','f'},
                 '6': {'a','c','d','e','g','f'},
                 '7': {'a','c','b'},
                 '8': {'a','c','d','e','b','g','f'},
                 '9': {'a','c','d','b','g','f'}}

I have a function created:

def guess_damaged(display, state, damaged):
    sorted_state = ''.join(sorted(state))
    sorted_damaged = ''.join(sorted(damaged))
    for key in display:
        templist = list(display[key])
        templist = sorted(templist)
        templist = ''.join(templist)
        if(templist == sorted_state):
            return {key for key,value in display.items() if all(sorted_damaged in value for sorted_damaged in sorted_state)}


print(guess_damaged(seven_segment, 'adeg', 'bf'))
print(guess_damaged(seven_segment, 'abed', 'cf'))
print(guess_damaged(seven_segment, '', 'abcdefg'))

My current output is shown below:

None
None
None

However, this is my desired output:

{'2'}
{'0'}
{'4', '5', '1', '8', '7', '6', '3', '0', '2', '9'}

How can I get the desired output?

Upvotes: 0

Views: 50

Answers (2)

Boseong Choi
Boseong Choi

Reputation: 2596

Solution

I think this is what you want:

seven_segment = {'0': {'a', 'c', 'd', 'e', 'b', 'f'},
                 '1': {'c', 'b'},
                 '2': {'a', 'd', 'e', 'b', 'g'},
                 '3': {'a', 'c', 'd', 'b', 'g'},
                 '4': {'g', 'c', 'f', 'b'},
                 '5': {'a', 'c', 'd', 'g', 'f'},
                 '6': {'a', 'c', 'd', 'e', 'g', 'f'},
                 '7': {'a', 'c', 'b'},
                 '8': {'a', 'c', 'd', 'e', 'b', 'g', 'f'},
                 '9': {'a', 'c', 'd', 'b', 'g', 'f'}}


def guess_damaged(display, state, damaged):
    return {
        key
        for key, value in display.items()
        if set(state) == (value - set(damaged))
    }


print(guess_damaged(seven_segment, 'adeg', 'bf'))
print(guess_damaged(seven_segment, 'abed', 'cf'))
print(guess_damaged(seven_segment, '', 'abcdefg'))

output:

{'2'}
{'0'}
{'7', '1', '5', '0', '9', '4', '2', '6', '3', '8'}

Explaination

set is very powerful built-in class. reference page about set
You can perform with set:

  • union(|)
  • intersect(&)
  • difference(-)
  • symmetric difference(^)
  • subset relations(<=, <, >, >=)
  • equality(==, !=)

Upvotes: 1

robert wallace
robert wallace

Reputation: 429

There is no value in the seven_segment dictionary that equals 'adeg' or 'abed' or '' when sorted, so the line with "if (templist == sorted_state):" never is true

Upvotes: 0

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