CODEWITHSUNDEEP
pythonpython-3.xlist
hsolo
hsolo

Reputation: 23

Why are different lists in the same index?

Currently im coding to calculate the number of elements in a row for a magic square and im testing it - first row has 3 elements, the second row has 4 elements and the third row has 3 elements im trying to get the code to make sure that all the rows have the same number of elements however im getting displayed the output : 

Enter filename :test
[3]
[4]
[3]

Im not sure what it means when the lists are shown "going down" like this, they are all in the same index of 0.

Current Code - 

r = input("Enter filename :")
while True:
    try:
        f = open(r,"r")
        break
    except:
        r = input("Enter the correct filename :")

while True: 
    line = f.readline()
    if not line:
        break
    a = line.split(' ')
    totalrow = len(a)
    m = []
    m.append(len(a))
    for x in m: 
        print(m[0])

Im not sure as to how to have these numbers in a list separately so i can compare them and apply validation

Upvotes: 0

Views: 74

Answers (1)

Guimoute
Guimoute

Reputation: 4649

You can simply create a list beforehand, iterate over the lines and append the length of the line.split to the list.

# Get the file.
r = input("Enter filename:")
while True:
    try:
        f = open(r, "r")
        break
    except FileNotFoundError:
        print(f"Could not locate a file named {r}.")
        r = input("Enter the correct filename: ")

# Count the rows for each line. 
elements_per_line = []
for line in f:  
    rows = len(line.split(" "))
    elements_per_line.append(rows)

# Do something with that information (`elements_per_line` == [2, 3, 2] now).
if sum(elements_per_line) != len(elements_per_line) * elements_per_line[0]:
    print("✗ Not all lines have the same size!")
else:
    print("✓ All lines have the same size.")

Upvotes: 1

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