Reputation: 43
I was wondering, whether it would be possible to assign a unique ID for every new class (not instance!).
Example of what I mean:
public class ChildObjectOne extends SuperClass {}
public class ChildObjectTwo extends SuperClass {}
public SuperClass {
private final int ID;
public SuperClass() {
this.ID = newID();
}
}
final ChildObjectOne childObjectOne = new ChildObjectOne();
final ChildObjectTwo childObjectTwo = new ChildObjectTwo();
System.out.println(childObjectOne.getID()); //prints 1
System.out.println(childObjectOne.getID()); //prints 2
childObjectOne = new ChildObjectOne();
childObjectTwo = new ChildObjectTwo();
System.out.println(childObjectOne.getID()); //prints 3
System.out.println(childObjectOne.getID()); //prints 4
What I want it to do instead is print 1 and 2 again. It should generate a new ID for every new class, but if I create a new instance of that class, I want the ID to stay the same.
I tried to achieve this using generics:
public SuperClass<T> {
private static int ID;
public SuperClass() {
this.ID = newID();
}
}
public class ChildObjectOne extends SuperClass<ChildObjectOne> {}
public class ChildObjectTwo extends SuperClass<ChildObjectTwo> {}
I was hoping, it would count passing a different T as a new class, but that didn't work. Instead the ID is the last one that was set.
How can I achieve this kind of ID system?
Upvotes: 1
Views: 1518
Reputation: 1464
To expand upon my comment, the class name will give you an unique String ID. If you want that ID to be a number you could do something like this:
class IdGenerator{
private static int counter = 0;
private static HashMap<String,Integer> classIdMap = new HashMap<>();
public static synchronized int getId(Class clazz){
if (classIdMap.containsKey(clazz.getName())) {
return classIdMap.get(clazz.getName());
} else {
classIdMap.put(clazz.getName(), ++counter);
return counter;
}
}
}
And then from your class you would do:
IdGenerator.getId(this.getClass());
The generated IDs might not be the same every time you run your app, depending on how it is structured. For example:
Scanner in = new Scanner(System.in);
if (in.nextInt() < 100) {
System.out.println("a = " + new Aclass().id); // a = 1
System.out.println("b = " + new Bclass().id); // b = 2
} else {
System.out.println("b = " + new Bclass().id); // b = 1
System.out.println("a = " + new Aclass().id); // a = 2
}
Upvotes: 1
Reputation: 339382
Class::getName
Each class in Java already carries a unique identifier: the fully-qualified name of the class. No need for you to add an identifier.
Access the fully-qualified name by calling Class::getName
.
For a class:
String.class.getName()
"java.lang.String"
For an object (an instance), call Object::getClass
, and then Class::getName
.
customer.getClass().getName()
com.example.invoicing.Customer
Upvotes: 1