Reputation: 11
I have two tables, Table 1 with multiple columns, name, ID number, address, etc. And Table 2 with columns, ID number 1 and ID number 2 and a few other columns.
I am trying to get a T-SQL query returning all rows in Table 1 with an indicator showing whether the ID number in Table 1 matches either ID_1 or ID_2 in Table 2. The result set would be all columns from Table 1 , plus the indicator “Matched” if the ID number in Table 1 matches either ID_1 or ID_2 in Table 2.
Result
T1.ID, Name, Address, ("Matched"/"Unmatched") ...
Also, would it be the same to do the opposite, meaning instead of the result including all rows from Table 1 that have a matching ID in ID_1 or ID_2 in Table 2, the result set would include only records from Table 1 where t1.ID = (T2.ID_1 or T2.ID_2)?
SELECT DISTINCT
CASE
WHEN (table1.ID = table2.ID_1 )
THEN 'Matched'
ELSE 'Unmatched'
END AS Status ,
table1.*
FROM
table1
LEFT JOIN
table2 ON table1.ID = table2.ID_1
UNION
SELECT DISTINCT
CASE
WHEN (table1.ID = table2.ID_2)
THEN 'Matched'
ELSE 'Unmatched'
END AS Status,
table1.*
FROM
table1
LEFT JOIN
table2 ON table1.ID = table2.ID_2
Upvotes: 1
Views: 1024
Reputation: 222432
I think that a correlated subquery with an exists
condition would be a reasonable solution:
select
t1.*,
case when exists (select 1 from table2 t2 where t1.id in (t2.id_1, t2.id_2))
then 'Matched'
else 'Unmatched'
end matched
from table1 t1
And the other way around:
select
t2.*,
case when exists (select 1 from table1 t1 where t1.id in (t2.id_1, t2.id_2))
then 'Matched'
else 'Unmatched'
end matched
from table2 t2
If you want to "align" the rows based on the match for the whole dataset at once, then you might want to try a full join
:
select t1.*, t2.*
from table1 t1
full join table2 t2 on t1.id in (t2.id_1, t2.id_2)
Upvotes: 1