CODEWITHSUNDEEP
pythondatedatetime
beepbeep-boop
beepbeep-boop

Reputation: 129

Python // Filter out certain dates from an array by comparison from today's date

I have this list of dates:

['2020-03-17 12:00:00', '2020-03-17 15:00:00', '2020-03-17 18:00:00', '2020-03-17 21:00:00', '2020-03-18 00:00:00', '2020-03-18 03:00:00', '2020-03-18 06:00:00', '2020-03-18 09:00:00', '2020-03-18 12:00:00', '2020-03-18 15:00:00', '2020-03-18 18:00:00', '2020-03-18 21:00:00', '2020-03-19 00:00:00', '2020-03-19 03:00:00', '2020-03-19 06:00:00', '2020-03-19 09:00:00', '2020-03-19 12:00:00', '2020-03-19 15:00:00', '2020-03-19 18:00:00', '2020-03-19 21:00:00']

It contains times with a 3 hour gap each and several dates upto 2020-3-19, in the format of YYYY-MM-DD HH-MM-SS.

Using date i can get today's date, and now i want to compare today's date to my list above and get all the dates that match today's current date and tommorow, i.e: Today is 2020-03-17, i want to get all dates with their times that match today and tommorow's date, meaning 2020-03-17 and 2020-03-18

from datetime import date
current_date = date.today()

This is for a small practice project in python for a weather api request. (I'm new to the python, i tried researching about this issue, it's quite hard to get results and it would be best to ask it here, might be a waste of time for you guys but it helps greatly~)

Thanks!

Upvotes: 0

Views: 341

Answers (3)

0buz
0buz

Reputation: 3503

Using dateutil.parser helps you avoid defining/handling a fixed datetime format. It handles that automatically for you.

from dateutil import parser
from datetime import date, timedelta

#timestamps=[your list of datatimes]

today = date.today()
tomorrow=today + timedelta(days=1)

result=[dt for dt in timestamps if today <= parser.parse(dt).date() <= tomorrow]

Upvotes: 0

a_guest
a_guest

Reputation: 36339

You can loop over the array and check whether the dates are current to today or tomorrow's date object:

from datetime import datetime, timedelta

today = datetime.now().date()
tomorrow = today + timedelta(days=1)

dates = [datetime.strptime(s, '%Y-%m-%d %H:%M:%S').date() for s in strings]
result = [date for date in dates if date in (today, tomorrow)]

Upvotes: 1

yatu
yatu

Reputation: 88305

You could define today and tomorrow's date beforehand, loop over the strings in the list, parse them appropiately using datetime.strptime, and see if the date part matches with either today or tomorrow's date:

from datetime import datetime, timedelta

today = datetime.today().date()
tomorrow = today + timedelta(days=1)

out = []
for i in l:
    date =  datetime.strptime(i, '%Y-%m-%d %H:%M:%S').date()
    if date == today or date == tomorrow:
        out.append(i)

print(out)

['2020-03-17 12:00:00',
 '2020-03-17 15:00:00',
 '2020-03-17 18:00:00',
 '2020-03-17 21:00:00',
 '2020-03-18 00:00:00',
 '2020-03-18 03:00:00',
 '2020-03-18 06:00:00',
 '2020-03-18 09:00:00',
 '2020-03-18 12:00:00',
 '2020-03-18 15:00:00',
 '2020-03-18 18:00:00',
 '2020-03-18 21:00:00']

Upvotes: 2

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