CODEWITHSUNDEEP
ansible
MUY Belgium
MUY Belgium

Reputation: 2452

Ansible fails to compare version with is version

I use Ansible 2.8.5. I could use ansible_facts.package but simple, let's use the following playbook.

  - debug:
     msg: "{{ { 'version':'5.52.2' } is version('6.0.0','>=') }}"

returns

   ..."msg" : True

How can I get a correct dot separated version correctly compared?

I read the official documentation and did not manage to understand how the function version is working. Some people even said that this should rise a TypeError exception. Nobody seems to understand how version is designed to work...

Upvotes: 0

Views: 1243

Answers (2)

Shreyash
Shreyash

Reputation: 456

Try this. refer Version Comparison. Provide the version in the string.

- hosts: localhost
  tasks:
    - set_fact:
            version1: "5.52.2"
            version2: "6.0.0"
    - debug:
            msg: "{{ version1  is version( version2  , '>=') }}"

Upvotes: 1

bosari
bosari

Reputation: 2000

Why don't you register the version first in a variable and then add a check. Then you can compare the content of the variable. Here is an example - 

failed_when: "'<version>{{ version }}</version>' not in this.content"
    - debug: msg=" version is {{ this.content.split('\n')[0].split('version')[1].split('>')[1].split('</')[0]}}"

Upvotes: 0

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