CODEWITHSUNDEEP
pythonregex
Foshiba
Foshiba

Reputation: 225

Regular expression to find a series of uppercase words in a string

text = "This is a TEXT CONTAINING UPPER CASE WORDS and lower case words. This is a SECOND SENTENCE."

pattern = '[A-Z]+[A-Z]+[A-Z]*[\s]+'

re.findall(pattern, text) gives an output --> 

['TEXT ', 'CONTAINING ', 'UPPER ', 'CASE ', 'WORDS ', 'SECOND ', 'SENTENCE ']

However, I want an output something like this --> 

['TEXT CONTAINING UPPER CASE WORDS', 'SECOND SENTENCE']

Upvotes: 4

Views: 8093

Answers (2)

anubhava
anubhava

Reputation: 785176

You may use this regex:

\b[A-Z]+(?:\s+[A-Z]+)*\b

RegEx Demo

RegEx Details:

  • \b: Word boundary
  • [A-Z]+: Match a word comprising only uppercase letters
  • (?:\s+[A-Z]+)*: Match 1+ whitespace followed by another word with uppercase letters. Match this group 0 or more times
  • \b: Word boundary

Code:

>>> s = 'This is a TEXT CONTAINING UPPER CASE WORDS and lower case words. This is a SECOND SENTENCE';
>>> print (re.findall(r'\b[A-Z]+(?:\s+[A-Z]+)*\b', s))
['TEXT CONTAINING UPPER CASE WORDS', 'SECOND SENTENCE']

Upvotes: 14

azro
azro

Reputation: 54148

  1. Improving regex, you want at least 2 uppercase letter, so use the dedicated syntax {2,} for 2 or more, and use word boundary to be sure to catch the whole word

    r'\b[A-Z]{2,}\b'

  2. Do the job for each sentence : find them with a basic regex, and for each sentence, look for the uppercase words, then save them in an array by joining with a space

    result = []
sentences = re.findall("[^.]+.", text)
for sentence in sentences:
    uppercase = re.findall(pattern, sentence)
    result.append(" ".join(uppercase))
print(result)  # ['TEXT CONTAINING UPPER CASE WORDS', 'SECOND SENTENCE']

In a list-comprehension, it looks like

res = [" ".join(re.findall(pattern, sentence)) for sentence in re.findall("[^.]+.", text)]

Upvotes: 1

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