CODEWITHSUNDEEP
pythonpython-3.xdictionary
selo_b
selo_b

Reputation: 1

finding key/value in dictionary

When I run this code:

capitals = {'France': 'Paris', 'Spain': 'Madrid', 'United Kingdom': 'London',
         'India': 'New Delhi', 'United States': 'Washington DC','Italy':'Rome',
        'Denmark': 'Copenhagen','Germany': 'Berlin','Greece': 'Athens',
        'Bulgaria': 'Sofia','Ireland': 'Dublin','Mexico': 'Mexico City'
        }

country = input('Please write a country >>> ')
country = country.title()

if country.isalpha():
    if country in capitals:
        print(f'The capital of {country} is', capitals.get(country))
    else:
        print('Sorry, I couldn\'t find this country in my list')
else:
    print('There\'s something wrong, please check the country name you\'ve entered')

and enter 'united states' or 'united kingdom' as input, it returns;

Please write a country >>> United Kingdom
There's something wrong, please check the country name you've entered

Couldn't find what I was doing wrong... Anyone could give me a hand?

Upvotes: 0

Views: 56

Answers (1)

No blyat
No blyat

Reputation: 136

The problem is that the isaplha() method takes into account the white spaces in the input strings 'united states' and 'united kingdom' and returns false. White spaces are not considered to be alphabet.

You can try this:

if country.replace(" ","").isalpha(): #Removing white spaces
    if country in capitals:
        print(f'The capital of {country} is', capitals.get(country))
    else:
        print('Sorry, I couldn\'t find this country in my list')
else:
    print('There\'s something wrong, please check the country name you\'ve entered')

This will remove the white spaces in input strings while checking the condition.

Upvotes: 1

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