CODEWITHSUNDEEP
python-3.xcurlpython-requests
Peter K.
Peter K.

Reputation: 587

cURL multipart/form-data with files to Python request

Am struggling to translate a working cURL command into an equivalent Python request. The cURL command is as follows: 

curl -X POST \
  http://localhost:3001/api/v1/document \
  -H 'Content-Type: multipart/form-data' \
  -F 'file=@/home/user1/test.pdf;type=application/pdf' \
  -F '[email protected];type=application/json'

Am using Python 3.6 and the request library and have been considering various approaches. One of those, which IMHO should work, but gives a Error: Multipart: Boundary not found error on the server is the following: 

url = 'http://localhost:3001/api/v1/document'
headers  = {'Content-Type': 'multipart/form-data'}
file = "/home/user1/test.pdf"

files = {
     'file': (file, open(file, 'rb'),'type=application/pdf'),
      'config': ('config.json',open('config.json','rb'),'type=application/json')
 } 

r = requests.post(url, files=files, headers=headers )

I have looked at various online "translaters", including https://curl.trillworks.com/ but none of them give a working answer. Also tried a number of variations, which I found in other posts, such as removing the content-type in the header, or using json.dump() instead of the open() function, but still, no success.

Any help would be greatly appreciated!

Upvotes: 0

Views: 1082

Answers (1)

Peter K.
Peter K.

Reputation: 587

The solution from Bertrand Martel did the trick in the end:

  1. Removing headers
  2. Removing 'type=' from both, the pdf and json files.

The working solution looks thus as follows:

url = 'http://localhost:3001/api/v1/document'

file = "/home/user1/test.pdf"

files = {
     'file': (file, open(file, 'rb'),'application/pdf'),
      'config': ('config.json',open('config.json','rb'),'application/json')
 } 

r = requests.post(url, files=files)

Upvotes: 1

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