CODEWITHSUNDEEP
pythonpython-3.xlist
Aaryansh Sahay
Aaryansh Sahay

Reputation: 71

How to get output by using multiple lists?

I'm trying to get a personalised message for each name corresponding to a mail defined by a list(a know how to get around this problem by using dictionary but dont know about lists).Can anyone help me by telling me how its done?

mail_id=['asd@g','nsg@g','psg@g']
names_list=['asd','nsg','psg']

for names in names_list:
    for mail in mail_id:
        msg='{}\n{}'.format(names,mail)
        print(msg)

the output which this gives is:

asd
asd@g
asd
nsg@g
asd
psg@g
nsg
asd@g
nsg
nsg@g
nsg
psg@g
psg
asd@g
psg
nsg@g
psg
psg@g

The desired output:

 asd
 asd@g
 nsg
 nsg@g
 psg
 psg@g

here once again we can use indices to get the desired output but it'll be long and tedious.

Upvotes: 1

Views: 67

Answers (4)

kederrac
kederrac

Reputation: 17322

if you like one line solution you could use a generator expression: 

print(*('\n'.join(t) for t in zip(names_list, mail_id)), sep='\n')

output:

asd
asd@g
nsg
nsg@g
psg
psg@g

Upvotes: 1

Joseph Chotard
Joseph Chotard

Reputation: 695

If they're guaranteed to be in the same order you can just use the following:

mail_id=['asd@g','nsg@g','psg@g']
names_list=['asd','nsg','psg']
for index, name in enumerate(names_list):
   print(name)
   print(mail_id[index])

Hope this helps!!

Upvotes: 2

Samira Kumar
Samira Kumar

Reputation: 521

You can use zip and enumerate to get the output.

for i, j in enumerate (zip(mail_id,names_list)):
    print (j[1])
    print (j[0])

asd
asd@g
nsg
nsg@g
psg
psg@g

Upvotes: 2

Ch3steR
Ch3steR

Reputation: 20659

You can use zip here.

for name,mail in zip(names_list,mail_id):
    print(f'{name}\n{mail}')

asd
asd@g
nsg
nsg@g
psg
psg@g

Upvotes: 3

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