CODEWITHSUNDEEP
pythondatabasesqlite
berry2971
berry2971

Reputation: 19

How to update row by row using python function in sqlite3?

This question is duplicated I think, but I couldn't understand other answers...

  1. Original table looks like this.
NAME    AGE SMOKE
John    25  None
Alice   23  None
Ken     26  None

  1. I will update SMOKE column in these rows,

  2. But I need to use output of function which was coded in python check_smoke(). If I input name to check_smoke(), then it returns "Smoke" or "Not Smoke".

  3. So final table would look like below:

NAME    AGE SMOKE
John    25  Smoke
Alice   23  Not Smoke
Ken     26  Not Smoke

I'm using sqlite3 and python3. How can I do it? Thank you for help!

Upvotes: 0

Views: 1256

Answers (1)

Serge Ballesta
Serge Ballesta

Reputation: 148900

You could use 1 cursor to select rows and another one to update them.

Assuming that the name of the table is smk (replace it by your actual name) and that con is an established connection to the database, you could do:

curs = con.cursor()
curs2 = con.cursor()
batch = 64            # size of a batch of records
curs.execute("SELECT DISTINCT name FROM smk")
while True:
    names = curs.fetchmany(batch)                             # extract a bunch of rows
    if len(names) == 0: break
    curs2.executemany('UPDATE smk SET smoke=? WHERE name=?',  #  and update them
              [(check_smoke(name[0]), name[0]) for name in names])
con.commit()

Upvotes: 1

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