Reputation: 627
I have written a find query, which works, the find query returns records where name and level exist
db.docs.find( { $and: [{name:{$exists:true}},{level:{ $exists:true}} ] },{_id:0, name:1}).sort({"name":1})
and now want to combine it with something like the code below which also works, but needs to be merged with the above to pull the correct data
db.docs.aggregate(
[
{
$project:
{
_id:0,
name: 1,
Honours:
{
$cond: { if: { $gte: [ "$level", 8 ] }, then: "True", else: "False" }
}
}
}
]
)
The find query returns records where name and level exist, but I need to enhance the result with new column called Honours, showing True of False depending on whether the level is gte (greater than or equal to 8)
So I am basically trying to combine the above find filter with the $cond function (which I found and modified example here : $cond)
I tried the below and a few other permutations to try and make find and sort with the $project and$cond aggregate, but it returned errors. I am just very new to how to construct mongodb syntax to make it all fit together. Can anyone please help?
db.docs.aggregate(
[{{ $and: [{name:{$exists:true}},{level:{ $exists:true}} ] },{_id:0, name:1}).sort({"name":1}
{
$project:
{
_id:0,
name: 1,
Honours:
{
$cond: { if: { $gte: [ "$level", 8 ] }, then: "True", else: "False" }
}
}
}
}
]
)
Upvotes: 1
Views: 508
Reputation: 17915
Try below aggregation pipeline :
db.docs.aggregate([
/** $match is used to filter docs kind of .find(), lessen the dataset size for further stages */
{
$match: {
$and: [{ name: { $exists: true } }, { level: { $exists: true } }]
}
},
/** $project works as projection - w.r.t. this projection it will lessen the each document size for further stages */
{
$project: {
_id: 0,
name: 1,
Honours: {
$cond: { if: { $gte: ["$level", 8] }, then: "True", else: "False" }
}
}
},
/** $sort should work as .sort() */
{ $sort: { name: 1 } }
]);
Upvotes: 0