CODEWITHSUNDEEP
apipostluagetresponse
C.V
C.V

Reputation: 969

Access REST API via lua script

Is there way to access rest api with pure lua script

GET / POST both way need to access and display response

i already tried

    local api = nil
    local function iniit()
    if api == nil then
      -- body
      api = require("http://api.com")
            .create()
            .on_get(function ()
                return {name = "Apple",
                        id = 12345}

            end)
        end
     end

Upvotes: 2

Views: 15679

Answers (1)

C.V
C.V

Reputation: 969

In linux , mac we can easily install luarocks , and then we can install curl package. It's easiest way to unix like os.


-- HTTP Get
local curl = require('curl')

curl.easy{
  url = 'api.xyz.net?a=data',
  httpheader = {
    "X-Test-Header1: Header-Data1",
    "X-Test-Header2: Header-Data2",
  },
  writefunction = io.stderr -- use io.stderr:write()
}
:perform()
:close()

In windows i faced several problems. Cant install luarocks correctly. then luarock install command not work correctl, etc..

In first dwnload lua from official site, and then create structure like (below web site)

http://fuchen.github.io/dev/2013/08/24/install-luarocks-on-windows/

then i download lua luadist http://luadist.org/

then i got same structure luadist extracted folder and lua folder.

merged luadist folder and lua folder Finaly we can use http.soket

local http=require("socket.http");

local request_body = [[login=user&password=123]]
local response_body = {}

local res, code, response_headers = http.request{
    url = "api.xyz.net?a=data",
    method = "GET", 
    headers = 
      {
          ["Content-Type"] = "application/x-www-form-urlencoded";
          ["Content-Length"] = #request_body;
      },
      source = ltn12.source.string(request_body),
      sink = ltn12.sink.table(response_body),
}

print(res)
print(code)

if type(response_headers) == "table" then
  for k, v in pairs(response_headers) do 
    print(k, v)
  end
end

print("Response body:")
if type(response_body) == "table" then
  print(table.concat(response_body))
else
  print("Not a table:", type(response_body))
end

IF YOU DO THESE STEPS CORRECTLY , THIS WILL BE WORK 1000% SURE

Upvotes: 1

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