CODEWITHSUNDEEP
kotlinjvm
Kali
Kali

Reputation: 461

Why the value of int variable changes after converting it to string index to int?

fun main(){
    val num=348597
    println(num.toString()[0].toInt())
}

I should be getting 3 as the output but I'm getting 51 instead.

Does anyone know why, or what I can do instead to get 3 as the result?

Upvotes: 0

Views: 247

Answers (2)

Kali
Kali

Reputation: 461

Yo, I found the easy way how to solve this problem. I was getting 51 because I was converting char to int directly and it was returning ASCII value or shit instead. So here is the code:

fun main(){
val num=348597
//use Character.getNumericValue() instead

println(Character.getNumericValue(num.toString()[0])) }

I found the answer here.

Upvotes: 0

laalto
laalto

Reputation: 152817

num.toString() gives you "348597". Taking [0] from it returns the first Char '3' which is a 16-bit unicode character value. Calling toInt() just converts the character value to an integer. In unicode the codepoints < 128 are the same as in ASCII and 51 is the value for the character '3'.

To get the character as a string representing "3", change toInt() to toString().

Upvotes: 2

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