CODEWITHSUNDEEP
google-apps-scriptgoogle-sheets
George Melencu
George Melencu

Reputation: 3

google sheet script doesn't enter the second for loop

I'm doing a loop in google sheets script, i'm trying to find a row in the "Inventar" sheet that has the same value found in the sheet "Fisa client" and then change the value of a cell in that row but it appears that it does not enter the second for. I'm new to this so i don't know what's the problem.

   function adaugabucati1(){
   var sheet = SpreadsheetApp.getActiveSpreadsheet();
   var ss=sheet.getSheetByName('Fisa client');
   var ss2=sheet.getSheetByName('Inventar');
   var data = ss.getRange("g9:l18").getValues();
   var data1=ss2.getDataRange().getValue();
   for(var i=0;i<data.length;i++){
        if(!data[i][0] == ""){
          var cod = ss.getRange(i+9,8).getValue();
          var buc = ss.getRange(i+9,10).getValue();
          for(var y=0;y<data1.length;y++){
              if(data1[y][5] == cod){ 
                 var bucati = data[y][7]-buc;
                 ss2.getRange(y+1,8).setValue(bucati);  
              }
            }  
        }

     }
   }

Upvotes: 0

Views: 61

Answers (1)

Tedinoz
Tedinoz

Reputation: 7949

The problem is in this line:
var data1=ss2.getDataRange().getValue();

getValue() returns only one value - the value of the top-left cell in the range.

When the if statement following the second loop evaluates data1[y][5], it returns "undefined" and the rest of the second loop is bypassed.

You need to change line#6 to:
var data1=ss2.getDataRange().getValues();
Note getValue() - > getValues()

Upvotes: 2

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