Reputation: 11
My code here
if (parent4 && parent5 && parent6 && (_state[tree][parent4]) + (_state[tree][parent5]) + (_state[tree][parent6]) !== 8) {
return false;
} else {
return true;
}
It works, and has some of the elements I want, namely that if the sum of the three _states !== 8
, it returns false
.
I'll try to explain the logic I'm trying to achieve as simply as I can:
if par4 + par5 + par6 !>= 8
return false
if par4 + par5 !>= 8
return false
if par4 OR par5 OR par6 !>= 8
return false
else
return true
I abbreviated the code for simplicity and ease of understanding.
Swapping around return false
and return true
and changing it to >=
doesn't work, because for all elements, even ones I don't mention here, it needs to go to return true
by default.
Upvotes: 0
Views: 60
Reputation: 29121
How about this?
if (parent4 && parent5 && parent6) {
if ((_state[tree][parent4] + _state[tree][parent4] + _state[tree][parent4]) !== 8) {
return false;
} else {
return true;
}
}
Or in a one-liner:
if (parent4 && parent5 && parent6 && (_state[tree][parent4] + _state[tree][parent4] + _state[tree][parent4]) !== 8) {
return false;
} else {
return true;
}
Upvotes: 1