Reputation: 29
I am creating a Class in vba (for excel) to process blocks of data. After some manipulation of a text file I end up with blocks of data (variable asdatablock() ) which I want to process in a For Loop
I created my own Class called ClDataBlock from which I can get key data by a simple call of the property required. 1st pass seems to work and I am now trying to expand my Let function to 2 argument but it’s not working. How do I specify the 2nd argument?
Dim TheDataBlock As New ClDataBlock
For i = 0 to UBound(asdatablock)
asDataBlockLine = Split(asdatablock(i), vbLf) ‘ split block into line
TheDataBlock.LineToProcess = asDataBlockLine(5) ‘allocate line to process by the class
Dvariable1 = TheDataBlock.TheVariable1
‘and so on for the key variables needed base don the class properties defined
Next i
In the Class Module the Let function takes 2 arguments
code extract of what I am looking at - 'in the class module
Dim pdMass As Double
Private pthelineprocessed As String
Public Property Let LineToProcess(stheline As String, sdataneeded As String)
pthelineprocessed = DeleteSpaces(Replace(stheline, vbLf, ""))
Dim aslinedatafield() As String
Select Case sdataneeded
'THIS IS AN EXTRACT FROM THE FUNCTION
'THERE ARE AS NUMBER OF CASES WHICH ARE DEALT WITH
Case Is = "MA"
aslinedatafield() = Split(pthelineprocessed, " ")
pdbMass = CDbl(aslinedatafield(2))
End select
End function
Public Property Get TheMass() As Double
TheMass = pdMass
End Property
'in the "main" module
Dim TheDataBlock As New ClDataBlock
For i = 0 to UBound(asdatablock)
TheDataBlock.LineToProcess = asDataBlockLines(5) 'Need to pass argument "MA" as well
dmass = TheDataBlock.TheMass
'and so on for all the data to be extracted
Next i
Upvotes: 0
Views: 561
Reputation: 8868
When a Property has 2 or more arguments, the last argument is what is getting assigned. In other words, the syntax is like this:
TheDataBlock.LineToProcess("MA") = asDataBlockLine(5)
This means you need to change the signature of your property:
Public Property Let LineToProcess(sdataneeded As String, stheline As String)
Upvotes: 0