CODEWITHSUNDEEP
pythonpython-3.xdictionarymax
Leockl
Leockl

Reputation: 2156

How to return the key with the largest value in a dictionary

Say I have a dictionary which looks like this:

dct = {'key1':('Hello, Python!', 1), 'key2':(10, 2), 'aa':(9.9, 3)}

How do I return the key which has the highest 2nd value, ie. the highest 2nd value between 1, 2 and 3 is 3, therefore the returned key is:

'aa'

Upvotes: 0

Views: 67

Answers (2)

Ch3steR
Ch3steR

Reputation: 20669

You can use max.

max(dct.items(),key=lambda x:x[1][1])
# ('aa', (9.9, 3))

If you just want 'aa'

max(dct.items(),key=lambda x:x[1][1])[0]
# 'aa'

Upvotes: 1

jpl
jpl

Reputation: 367

Sort the dictionary by values (item[1] when you parse dct.items()), and especially by the second element of these values (item[1][1]). Then your max is the first element of the sorted list.

ordered_keys = [k for k, v in sorted(dct.items(), key=lambda item: item[1][1], reverse=True)]
best = ordered_keys[0]

Upvotes: 1

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