CODEWITHSUNDEEP
pythonfile
witolo
witolo

Reputation: 59

Reading values from a file

My task is to read 10 numbers from a ,txt file and then print their sum:

f = open("data.txt", "r")
sumofn=0
for i in range(1, 10):
    x = f.readline(i)
    x = int(x)
    sumofn += x

print(sumofn)

Unfortunately, I get this error:

ValueError: invalid literal for int() with base 10: '\n'

Upvotes: 0

Views: 51

Answers (3)

Osama
Osama

Reputation: 94

Here is the simple solution. If your values are comma separated, you can use the split() method:

f = open("data.txt", "r")
sumofn = 0
for i in range(1, 10):
    for x in f.readlines():
            x = int(x)
            sumofn += x

print(sumofn)

Here is also the split() method. It is used if your values are comma separated and space separated:

f = open("data.txt", "r")
sumofn = 0
for i in range(1, 10):
    for x in f.readlines():
        y = x.split(',')
        for x in y:
            x = int(x)
            sumofn += x

print(sumofn)

Upvotes: 4

SakuraFreak
SakuraFreak

Reputation: 315

Regexp is your best friend

with open('data.txt', 'r') as f:
     print(sum([int(i) for i in f.read().split('\n') if i != '']))

btw '\n' means it's a linebreak; the enter you press while writing text file. Because it has '\n' when you read the file.

Upvotes: 0

Perfect
Perfect

Reputation: 1646

I guess that your file has int values only because you used conversion int(). In this case, you can use regex pattern r'\d+' simply (instead of the r'\d+(\.\d+)?') but the following code covers the case that the file contains float values.

import re
result = 0
with open('data.txt', 'r') with f:
    line = f.readline()
    match = re.search(r'\d+(\.\d+)?', line)
    if match:
        result += float(match.group())
print(result)

Please give it a shot.

Upvotes: 0

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