CODEWITHSUNDEEP
pythonregexlist
user9092346
user9092346

Reputation:

Splitting String in List but keeping the delimiter

I have a list of strings:

List = ['aaa', 'bbb ccc', 'ddd (eee)']

I want to split elements that have parantheses either at the blank before the "(" or at the "(" in case that there is no blank ahead. But in this case, I want to keep the parantheses. So far I have come up with the following code that works if there is a blank:

for l in List:
   if re.search('\(', l) != None:
       a,b = re.split(' (?=\()', l)
       print('True')
       List_2.append(a)
       List_2.append(b)
   else:
       List_2.append(l)

print(List_2)

Two Questions: First, is there a cleaner version of this, maybe using list comprehension. Second, how do I capture a case without a blank 'fff(ggg)'.

The final list should then look like this:

List_correct['aaa', 'bbb ccc', 'ddd', '(eee)', 'fff', '(ggg)']

Upvotes: 0

Views: 70

Answers (1)

Shubham Sharma
Shubham Sharma

Reputation: 71689

Code:

List = ['aaa', 'bbb ccc', 'ddd (eee)', 'fff(ggg)']
result = [subitem for item in List for subitem in re.split(r"(?:\b|\s)(?=\()", item)]

Output:

>>>print(result)
['aaa', 'bbb ccc', 'ddd', '(eee)', 'fff', '(ggg)']

Upvotes: 3

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