CODEWITHSUNDEEP
pythonjson
Mustafa Ghiya
Mustafa Ghiya

Reputation: 9

IndentationError in python - what is wrong in my code?

import requests
import json

url='https://www.nseindia.com/api/option-chain-indices?symbol=NIFTY'    
headers= {'user-agent':'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.162 Safari/537.36',
"accept-language":"en-US,en;q=0.9","accept-encoding":"gzip, deflate"} 
def fetch_oi():  
r=requests.get(url,headers=headers).json()
print(r)
with open("oidata.json","w") as files:
    files.write(json.dumps(r,indent=4, sort_keys=True))

def main():
    fetch_oi()


if __name__=='__main__':
    main()

** in this code i'm getting error in r=requests.get(url,headers=headers).json() ^ IndentationError: expected an indented block

what i'm doing wronge? plzz help

Upvotes: 0

Views: 648

Answers (6)

Vishal Sheth
Vishal Sheth

Reputation: 160

Issue is in the body of 

def fetch_oi():

Put space to the body

My suggestions is to use sublime IDE. So, when you select the content you can visible the content that you have used space or tab. Also using tab is the good approach rather than space

I have seen that you have used space. So adjusting and using space will make you troublesome at long run.

Upvotes: 0

Victor
Victor

Reputation: 2909

The body of your function fetch_oi is unindented.

import requests
import json

url='https://www.nseindia.com/api/option-chain-indices?symbol=NIFTY'    
headers= {'user-agent':'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.162 Safari/537.36', "accept-language":"en-US,en;q=0.9","accept-encoding":"gzip, deflate"} 

def fetch_oi():  
    r=requests.get(url,headers=headers).json()
    print(r)

    with open("oidata.json","w") as files:
        files.write(json.dumps(r,indent=4, sort_keys=True))

def main():
    fetch_oi()

if __name__=='__main__':
    main()

Upvotes: 1

hjbello
hjbello

Reputation: 651

I believe it is clear that you need

def fetch_oi():  
    r=requests.get(url,headers=headers).json()
    print(r)
    with open("oidata.json","w") as files:
        files.write(json.dumps(r,indent=4, sort_keys=True))

instead of what you have (that is one tab more in fetch_io). In python you have to be careful with tabs. You need one identation level after each function. Take a look here: https://docs.python.org/2.0/ref/indentation.html

Upvotes: 2

Nathan Wride
Nathan Wride

Reputation: 965

The code in a function definition needs to be indented.

import json

url='https://www.nseindia.com/api/option-chain-indices?symbol=NIFTY'    
headers= {'user-agent':'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.162 Safari/537.36',
"accept-language":"en-US,en;q=0.9","accept-encoding":"gzip, deflate"} 

def fetch_oi():  
    r=requests.get(url,headers=headers).json()
    print(r)
    with open("oidata.json","w") as files:
        files.write(json.dumps(r,indent=4, sort_keys=True))

def main():
    fetch_oi()


if __name__=='__main__':
    main()

Python depends heavily on correct indentation, see: https://www.w3schools.in/python-tutorial/concept-of-indentation-in-python/

Upvotes: 3

Kasinath PS
Kasinath PS

Reputation: 46

intend lines after def fetch_oi():

Upvotes: 0

JrmDel
JrmDel

Reputation: 462

After your def fetch_oi(): you are supposed to indent the line r=requests.get(url,headers=headers).json() since it is a function

def fetch_oi():  
    r=requests.get(url,headers=headers).json()
    print(r)

then depending on where your function ends, you should keep indenting

Upvotes: 2

Related Questions