Reputation: 1263
My application needs to display a popup near the cursor position of any active application when certain conditions are met (known by my app).
So I would like to display the form (without stealing the focus from the active application). I tried using ShowWindow with the SW_SHOWNOACTIVATE param but, this way, the my form is displayed under the currently active form.
How can I force my form to be displayed on top of any form active on the screen without stealing the input focus?
Thanks.
Upvotes: 4
Views: 1294
Reputation: 13690
What you want is to use the TopMost property of the form you want to stay on top.
Upvotes: 1
Reputation: 2324
You need to add a bit of plumbing to the pop-up form so you can override the WM_ACTIVATE message:
protected override void WndProc(ref Message m)
{
if (m.Msg == WM_ACTIVATE)
{
if (((int)m.WParam & 0xFFFF) != WA_INACTIVE)
{
if (m.LParam != IntPtr.Zero)
{
SetActiveWindow(m.LParam);
}
else
{
// Could not find sender, just in-activate it.
SetActiveWindow(IntPtr.Zero);
}
}
}
base.WndProc(ref m);
}
Make sure you add the following to your pop-up form as well:
[DllImport("user32.dll")]
private extern static IntPtr SetActiveWindow(IntPtr handle);
private const int WM_ACTIVATE = 6;
private const int WA_INACTIVE = 0;
You can use the pop-up form as you would any other, by calling Show() on it. You can make it the top-most window through the TopMost property, as with other forms.
Upvotes: 0