Reputation: 3
I'm trying to make a logarithm calculator and got stuck—it doesn't print out a value. The problem may be at lines 15 or 24 or both. How can I make it print the value (all written in C).
Here's the full code:
#include <stdio.h>
#include <stdlib.h>
// Finds base 10 logarithms
int main()
{
float result;
float base = 10.0;
float multiplier = 1.0;
// float counter1 = 0.0;
// float counter2 = 0;
printf("Input result: ");
scanf("%l", result);
// Solves for all results above the base
if(result > base) {
while(result > multiplier) {
multiplier = multiplier * multiplier; // the multiplier has to check non-whole numbers
multiplier += 0.001;
} // division
}
printf("Your exponent is: %l \n", &multiplier);
printf("Hello mathematics!");
return 0;
}
All help appreciated, Xebiq
Upvotes: 0
Views: 181
Reputation: 1885
you should delete &
in printf
,and add &
in scanf
.
printf("Your exponent is: %f \n", multiplier);
scanf("%f", &result);
and use %f
in them.
and with base 10
I suggest this function to calculate log:
unsigned int Log2n(unsigned int n)
{
return (n > 1) ? 1 + Log2n(n / 10) : 0;
}
also you should know about Floating-point numbers here:
multiplier += 0.001;
probably exactly 0.001
won't be added to multiplier
when I debugged this 0.00100005
was being add to multiplier
in my compiler.(which will affect multiplying)
Upvotes: 1