CODEWITHSUNDEEP
c++clang++
user10837227
user10837227

Reputation:

Is there a way to save "char * argv[]" to a variable in C++?

I'd like to be able to save argv into a struct so that it can be passed to functions like so:

struct Parameters {
    int argc;
    char * argv[];
};

void Start(
    Parameters P
) {

};

int main (
    int argc,
    char * argv []
) {
    Parameters P;
    P.argc = argc;
    P.argv = & argv;


    return 0;
}

But with:

clang++ -std=c++2a -stdlib=libc++ -rtlib=compiler-rt -Ofast Start.cpp -o Start && ./Start;

I'm getting this error:

Start.cpp:21:9: error: array type 'char *[]' is not assignable

Is there a way of saving argv to a variable? Any help would be very much appreciated.

Upvotes: 0

Views: 1178

Answers (2)

Loki Astari
Loki Astari

Reputation: 264461

A simple way is to convert it to a vector of strings:

int main(int argc, char* argv[])
{
    // Note: use argv + 1 to skip the application name in args.
    //       If you want to include the application name then don't use
    //       the +1
    std::vector<std::string>    args(argv + 1, argv + argc);

    // Now this can be passed to functions easily.
    // args.size()  == number of arguments.
    // args[x] == the string for argument x

}

Upvotes: 2

Jeffrey
Jeffrey

Reputation: 11410

You can simply change to:

struct Parameters  
{
    int argc;
    char ** argv;
};

Your argv array of pointers to char will decay to a pointer to pointer to char.

Then, your main becomes simpler, with:

P.argv = argv;

Upvotes: 2

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