CODEWITHSUNDEEP
vimfind-replace
breezymri
breezymri

Reputation: 4343

vim: how to find words by matching first part, remove first part and then add a string to the end of word

In our code, we have non-standard naming conventions for our variables. For example, we have a category identifier that are attached to many variables in a file, like: usa_foo, bar_usa, where usa is the category identifier. I'd like to convert all these names with a standard of placing the category id in the end, so usa_foo would turn into foo_usa. Since these variables are often embedded in expressions, they could be followed by a few possible characters, which in this case (hashicorp hcl language), are mostly ", ], , or whitespace. For example, I'd like to turn:

usa_foo = something
something "${var.usa_foo}"
b = [var.usa_foo, var.bar_usa]
bar_usa

into:

foo_usa = something
something "${var.foo_usa}"
b = [var.foo_usa, var.bar_usa]
bar_usa

I know how to do find and replace if I know the character that follows the word, say ". Then it would be

%s/usa_\(\w*\)"\(.*\)/\1_usa"\2/g

However, I'm not sure how I can match multiple ending characters and still do the same thing.

Upvotes: 0

Views: 221

Answers (1)

SergioAraujo
SergioAraujo

Reputation: 11800

Using very magic to avoid backslash

:%s/\v(usa)(_)(foo)/\3\2\1

\v ................... very magic
() ................... regex group with no backslash

NOTE: We keep the second group in the middle, just exchange 1 for 3

Of course, if you have other occurrences at the same line you should add /g

Upvotes: 1

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