CODEWITHSUNDEEP
iosswiftregexstring
user12281762
user12281762

Reputation:

Regex pattern match and replace in Swift

I have strings like follows :

Hi this is %1$s, product %2$s Hi this is %2$s, product %2$s

I want to replace %1$s by {0}, and %2$s by {1} and so on..

I have tried to make:

let range = NSRange(location: 0, length: myString.count)
var regex = try! NSRegularExpression(pattern: "%[1-9]\\$s", options: [])
var newStr = regex.stringByReplacingMatches(in: myString, options: [], range: range, withTemplate: "XXXX")

Anyone can help me, please!

Upvotes: 1

Views: 704

Answers (1)

Larme
Larme

Reputation: 26006

Your pattern is wrong, you have at the start [a-z], so you aren't detecting anything.

Also, prefers utf16 count with NSStuff (because with NSString, it's UTF16)

let myString = "Hi this is %1$s, product %2$s Hi this is %2$s, product %2$s"

let range = NSRange(location: 0, length: myString.utf16.count)
var regex = try! NSRegularExpression(pattern: "%(\\d+)\\$s", options: [])
var newStr = regex.stringByReplacingMatches(in: myString, options: [], range: range, withTemplate: "{$1}")
print(newStr)

Output:

$>Hi this is {1}, product {2} Hi this is {2}, product {2}

Some explanation on %(\d+)\$s (and then redo a \ for Swift strings).
% : Detect "%"
\d+: Detect number (including 12 which weren't your case before)
(\d+): Detect number, but in a capture group
\$: Detect "$" (need an escape because it's a special char in regex)
s: Detect "s"

So there are two groups: The whole (corresponding to the whole regex match), and the numbers. The first one would be $0, and the second one $1, that's why I used {$1} in the template.

NB: I used https://regex101.com to check the pattern.

With increment, you can't do it with the template. You have to enumerate all the matches, do the operation and replace.

var myString = "Hi this is %1$s, product %2$s Hi this is %2$s, product %2$s"
let range = NSRange(location: 0, length: myString.utf16.count)
var regex = try! NSRegularExpression(pattern: "%(\\d+)\\$s", options: [])
let matches = regex.matches(in: myString, options: [] , range: range)
matches.reversed().forEach({ aMatch in
    let fullNSRange = aMatch.range
    guard let fullRange = Range(fullNSRange, in: myString) else { return }
    let subNSRange = aMatch.range(at: 1)
    guard let subRange = Range(subNSRange, in: myString) else { return }
    let subString = myString[subRange]
    guard let subInt = Int(subString) else { return }
    let replacement = "{" + String(subInt + 1) + "}"
    myString.replaceSubrange(fullRange, with: replacement)
})

Upvotes: 1

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